Concept explainers
Interpretation:
The percentage yield when
Concept introduction:
Answer to Problem 6PE
The percentage yield when
Explanation of Solution
The balanced equation for the reaction sodium phosphate with calcium nitrate solution is given below.
Therefore,
Therefore mole to mole ratio is given below.
Therefore, two conversion factors from the mole-to-mole ratio are given below.
The conversion factor to obtain moles of
The molar mass of oxygen is
The molar mass of sodium is
The molar mass of phosphorus is
Therefore, the molar mass of
Therefore, the conversion factor to obtain moles of
The molar mass of oxygen is
The molar mass of calcium is
The molar mass of phosphorus is
Therefore, the molar mass of
Therefore, the conversion factor to obtain grams of
The formula to calculate the mass of
The mass of
Substitute the mass of
The percentage yield is calculated by the formula given below.
The actual yield is
The ideal yield is
Substitute the value of actual yield and ideal yield in equation (1).
Therefore, the percentage yield when
The percentage yield when
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Chapter 10 Solutions
Introductory Chemistry: An Active Learning Approach
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