Concept explainers
Acidic oxides such as carbon dioxide react with basic oxides like calcium oxide
Interpretation:
The balanced equations representing the reactions and the percent composition by mass of each reactant in the sample are to be determined with given mass and volume of carbon dioxide, pressure, and volume.
Concept Introduction:
The ideal gas equation elaborates the physical properties of gases by relating the pressure, volume, temperature, and number of moles with each other with the help of four gas laws. This can be shown by
A balanced chemical equation follows the law of conservation of mass, according to which the number of different atoms in reactant side and product side must be equal.
The number of moles can be calculated as:
Here, m is the number of moles, wt is the given mass of compound, and M is the molar mass of the compound.
The conversion of temperature from degree Celsius to Kelvin can be done by using the formula given below:
The relationship between
To convert milliliters into liters, the conversion factor is
Answer to Problem 169AP
Solution:
(a)
The balanced chemical equations for the two reactions are as:
(b)
Percent by mass of
Explanation of Solution
a)Equations representing given two reactions
The balanced reaction of calcium oxide with carbon dioxide is as
The balanced reaction of barium oxide with carbon dioxide is as
b) The percent composition by mass of the mixture
The combined mass for mixture of BaO and CaOis
Both the salts are mixed in a flask of volume
The equation for an ideal gas is as
For
The conversion of temperature from degree Celsius to Kelvin can be done as follows:
The absolute value of
The pressure is
Convert mmHg to atm as:
Substitute the values
After the completion of reaction:
The pressure of
Convert mmHg to atm as:
Substitute the values
So, the quantity of carbon dioxide spent in the reaction is determined as
The ratio of number of moles of carbon dioxide and
So, the number of moles of the mixture is determined as
The mass of the sample is
Consider the mass of
So, the mass of
The molar mass of
The molar mass of
The number of moles can be calculated as
Here, m is the number of moles, wt is the given mass of compound, and M is the molar mass of the compound.
So, the moles of sample are as
Substitute the values
This can be rearranged as
So, the mass of
The mass of
Now, the percent by mass of
For
For
Hence, the percent by mass of
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Chapter 10 Solutions
Chemistry
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