In water conservation, chemists spread a thin film of a certain inert material over the surface of water to cut down on the rate of evaporation of water in reservoirs. This technique was pioneered by Benjamin Franklin three centuries ago. Franklin found that 0.10 mL of oil could spread over the surface of water about 40 m 2 in area. Assuming that the oil forms a monolayer, that is. a layer that is only one molecule thick, estimate the length of each oil molecule in nanometers ( 1 nm = 1 × 10 -9 m ) .
In water conservation, chemists spread a thin film of a certain inert material over the surface of water to cut down on the rate of evaporation of water in reservoirs. This technique was pioneered by Benjamin Franklin three centuries ago. Franklin found that 0.10 mL of oil could spread over the surface of water about 40 m 2 in area. Assuming that the oil forms a monolayer, that is. a layer that is only one molecule thick, estimate the length of each oil molecule in nanometers ( 1 nm = 1 × 10 -9 m ) .
Solution Summary: The author explains that the length of each oil molecule in nanometres is to be estimated. The conversion factor is a tion obtained from the relationship between the units.
In water conservation, chemists spread a thin film of a certain inert material over the surface of water to cut down on the rate of evaporation of water in reservoirs. This technique was pioneered by Benjamin Franklin three centuries ago. Franklin found that 0.10 mL of oil could spread over the surface of water about
40 m
2
in area. Assuming that the oil forms a monolayer, that is. a layer that is only one molecule thick, estimate the length of each oil molecule in nanometers
(
1 nm = 1
×
10
-9
m
)
.
13. (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the
molecule depicted below.
Bond B
Bond A
Bond C
a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in
appropriate boxes.
Weakest
Bond
Strongest
Bond
b. (4pts) Consider the relative stability of all cleavage products that form when bonds A,
B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B,
and C are all carbon radicals.
i. Which ONE cleavage product is the most stable? A condensed or bond line
representation is fine.
ii. Which ONE cleavage product is the least stable? A condensed or bond line
representation is fine.
c. (5pts) Use principles discussed in lecture, supported by relevant structures, to
succinctly explain the why your part b (i) radical is more stable than your part b(ii)
radical. Written explanation can be no more than one-two succinct sentence(s)!
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Statifically more chances to abstract one of these 6H
11. (10pts total) Consider the radical chlorination of 1,3-diethylcyclohexane depicted below. 4
4th total
• 6H total
래
• 4H total
21 total
ZH
2H
Statistical
H < 3° C-H weakest
-
product
abstraction here
bund
leads to thermo favored
a) (6pts) How many unique mono-chlorinated products can be formed and what are the
structures for the thermodynamically and statistically favored products?
Product
6
Number of Unique
Mono-Chlorinated Products
Thermodynamically
Favored Product
Statistically
Favored Product
b) (4pts) Draw the arrow pushing mechanism for the FIRST propagation step (p-1) for the
formation of the thermodynamically favored product. Only draw the p-1 step. You do
not need to include lone pairs of electrons. No enthalpy calculation necessary
H
H-Cl
Waterfox
10. (5pts) Provide the complete arrow pushing mechanism for the chemical transformation →
depicted below
Use proper curved arrow notation that explicitly illustrates all bonds being broken, and
all bonds formed in the transformation.
Also, be sure to include all lone pairs and formal charges on all atoms involved in the
flow of electrons.
CH3O
II
HA
H
CH3O-H
H
①
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
The Creation of Chemistry - The Fundamental Laws: Crash Course Chemistry #3; Author: Crash Course;https://www.youtube.com/watch?v=QiiyvzZBKT8;License: Standard YouTube License, CC-BY