The velocity is to be converted from m/s to mph . Concept introduction: Conversion factors are used to convert units of measurement of the same quantity without changing thevalue. Conversion factors are derived from the unity bracket method of unit conversion, which consists of a fraction derived from the equality. The units of the denominator and the numerator are different. The use of a conversion factor to solve numerical problems is called dimensional analysis.

Question

A typical candy bar weighs about 2 oz (1.00 oz = 28.4 g).(a) Assuming that a candy bar is 100% sugar and that 1.0 g of sugar is equivalent to about 4.0 Calories of energy, calculate the energy (in kJ) contained in a typical candy bar.(b) Assuming that your mass is 58 kg and you convert chemical potential energy to work with 100% efficiency, how high would you have to climb to work off the energy in a candy bar? (Potential energy = mass × g × height, where g = 9.8 m/s2.)(c) Why is your actual conversion of potential energy to work less than 100% efficient?

Answer 1

Question

Chapter 1, Problem 2KSP

Interpretation Introduction

Interpretation:

The velocity is to be converted from m/s to mph.

Concept introduction:

Conversion factors are used to convert units of measurement of the same quantity without changing thevalue.

Conversion factors are derived from the unity bracket method of unit conversion, which consists of a fraction derived from the equality. The units of the denominator and the numerator are different.

The use of a conversion factor to solve numerical problems is called dimensional analysis.

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Students have asked these similar questions

A typical candy bar weighs about 2 oz (1.00 oz = 28.4 g).(a) Assuming that a candy bar is 100% sugar and that 1.0 g of sugar is equivalent to about 4.0 Calories of energy, calculate the energy (in kJ) contained in a typical candy bar.(b) Assuming that your mass is 58 kg and you convert chemical potential energy to work with 100% efficiency, how high would you have to climb to work off the energy in a candy bar? (Potential energy = mass × g × height, where g = 9.8 m/s2.)(c) Why is your actual conversion of potential energy to work less than 100% efficient?

The calorie (4.184 J) was originally defined as the quantity of energy required to raise the temperature of 1.00 g of liquid water 1.00°C. The British thermal unit (Btu) is defined as the quantity of energy required to raise the temperature of 1.00 lb of liquid water 1.00°F.(a) How many joules are in 1.00 Btu (1 lb 453.6 g; a changeof 1.0°C= 1.8°F)?(b) The therm is a unit of energy consumption and is defined as 100,000 Btu. How many joules are in 1.00 therm?(c) How many moles of methane must be burned to give1.00 therm of energy? (Assume water forms as a gas.)(d) If natural gas costs $0.66 per therm, what is the cost per moleof methane? (Assume natural gas is pure methane.)(e) How much would it cost to warm 318 gal of water in a hottub from 15.0°C to 42.0°C (1 gal 3.78 L)?

Consider the two spheres shown here, one made of silver andthe other of aluminum. (a) What is the mass of each spherein kg? (b) The force of gravity acting on an object is F = mg,where m is the mass of an object and g is the acceleration ofgravity (9.8 m/s2). How much work do you do on each sphereit you raise it from the floor to a height of 2.2 m? (c) Does theact of lifting the sphere off the ground increase the potentialenergy of the aluminum sphere by a larger, smaller, orsame amount as the silver sphere? (d) If you release thespheres simultaneously, they will have the same velocitywhen they hit the ground. Will they have the same kineticenergy? If not, which sphere will have more kinetic energy?[Section 1.4]