Chapter 0.7, Problem 14E

To determine

To calculate: The perimeter of a rectangular room which is $\text{12}\frac{\text{1}}{\text{2}}\text{feet}$ wide and $\text{14feet}$ long.

Answer to Problem 14E

The perimeter of the rectangular room $\text{12}\frac{\text{1}}{\text{2}}\text{feet}$ wide and $\text{14feet}$ long is $\text{53 feet}$ .

Explanation of Solution

Given information:

A rectangular room is $\text{12}\frac{\text{1}}{\text{2}}\text{feet}$ wide and $\text{14feet}$ long.

Formula used:

Perimeter $\left(P\right)$ of a rectangle with length $\left(l\right)$ and breadth $\left(b\right)$ is denoted by $P=2\left(l+b\right)$ .

Calculation:

Consider the given statement that rectangular room is $\text{12}\frac{\text{1}}{\text{2}}\text{feet}$ wide and $\text{14feet}$ long.

Recall that a perimeter $\left(P\right)$ of a rectangle with length $\left(l\right)$ and breadth $\left(b\right)$ is denoted by $P=2\left(l+b\right)$ .

Apply it,

  $\begin{array}{c}P=\text{2×}\left(\text{12}\frac{\text{1}}{\text{2}}\text{+14}\right)\text{feet}\\ \text{=2×}\left(\text{12}\text{.5+14}\right)\text{feet}\\ \text{=2×26}\text{.5 feet}\\ \text{=53 feet}\end{array}$

Thus, the perimeter of the rectangular room $\text{12}\frac{\text{1}}{\text{2}}\text{feet}$ wide and $\text{14feet}$ long is $\text{53 feet}$ .