Chapter 0.11, Problem 3E

To determine

The probability of the given data.

Answer to Problem 3E

  $P\left(quaterornickel\right)=\frac{1}{2}$

Explanation of Solution

Given :

  $\begin{array}{l}nickel=70\\ \dim es=100\\ quarters=80\\ One-dollarcoin=50\end{array}$

Solution:

  $\begin{array}{l}totaloutcome=70+100+80+50\\ totaloutcome=300\end{array}$

Probability:

  $\mathrm{Pr}obability=\frac{probableoutcome}{totaloutcome}$

Probable outcome = 80+70=150

  $\begin{array}{l}P\left(quaterornickel\right)=\frac{80+70}{300}=\frac{150}{300}\\ P\left(quaterornickel\right)=\frac{1}{2}\end{array}$