Algebra 1
Algebra 1
1st Edition
ISBN: 9780078884801
Author: McGraw-Hill/Glencoe
Publisher: Glencoe/McGraw-Hill School Pub Co
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Chapter 0.5, Problem 4E
To determine

To find: The simplified value of the expression 14.1(2.9) .

Expert Solution & Answer
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Answer to Problem 4E

The simplified value of the expression 14.1(2.9) is 40.89 .

Explanation of Solution

Given information:

The expression 14.1(2.9) .

Formula used:

Product of two real numbers is obtained when they are multiplied together. That is two or more numbers are separated by multiplication signs (),× or  .

Product of two negative integers is always positive.

Calculation:

Consider the expression 14.1(2.9) .

Recall that product of two real numbers is obtained when they are multiplied together. That is two or more numbers are separated by multiplication signs (),× or  .

Simplify it,

  14.1(2.9)=+(14.12.9)=40.89

Thus, the simplified value of the expression 14.1(2.9) is 40.89 .

Chapter 0 Solutions

Algebra 1

Ch. 0.2 - Prob. 5ECh. 0.2 - Prob. 6ECh. 0.2 - Prob. 7ECh. 0.2 - Prob. 8ECh. 0.2 - Prob. 9ECh. 0.2 - Prob. 10ECh. 0.2 - Prob. 11ECh. 0.2 - Prob. 12ECh. 0.2 - Prob. 13ECh. 0.2 - Prob. 14ECh. 0.2 - Prob. 15ECh. 0.2 - Prob. 16ECh. 0.2 - Prob. 17ECh. 0.2 - Prob. 18ECh. 0.2 - Prob. 19ECh. 0.2 - Prob. 20ECh. 0.2 - Prob. 21ECh. 0.2 - Prob. 22ECh. 0.2 - Prob. 23ECh. 0.2 - Prob. 24ECh. 0.2 - Prob. 25ECh. 0.2 - Prob. 26ECh. 0.2 - Prob. 27ECh. 0.2 - Prob. 28ECh. 0.2 - Prob. 29ECh. 0.2 - Prob. 30ECh. 0.2 - Prob. 31ECh. 0.2 - Prob. 32ECh. 0.2 - Prob. 33ECh. 0.2 - Prob. 34ECh. 0.2 - Prob. 35ECh. 0.3 - Prob. 1ECh. 0.3 - Prob. 2ECh. 0.3 - Prob. 3ECh. 0.3 - Prob. 4ECh. 0.3 - Prob. 5ECh. 0.3 - Prob. 6ECh. 0.3 - Prob. 7ECh. 0.3 - Prob. 8ECh. 0.3 - Prob. 9ECh. 0.3 - Prob. 10ECh. 0.3 - Prob. 11ECh. 0.3 - Prob. 12ECh. 0.3 - Prob. 13ECh. 0.3 - Prob. 14ECh. 0.3 - Prob. 15ECh. 0.3 - Prob. 16ECh. 0.3 - Prob. 17ECh. 0.3 - Prob. 18ECh. 0.3 - Prob. 19ECh. 0.3 - Prob. 20ECh. 0.3 - Prob. 21ECh. 0.3 - Prob. 22ECh. 0.3 - 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