Algebra 1
Algebra 1
1st Edition
ISBN: 9780078884801
Author: McGraw-Hill/Glencoe
Publisher: Glencoe/McGraw-Hill School Pub Co
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Chapter 0.4, Problem 18E
To determine

To calculate: The simplified form of 715215 .

Expert Solution & Answer
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Answer to Problem 18E

The simplified form of 715215 is 13 .

Explanation of Solution

Given information:

The statement “ 715215 .”

Formula used:

When two or more fractions with same denominators are added or subtracted then only numerators are added or subtracted , denominator remains unchanged.

Consider the provided statement “ 715215 .”

Recall that when two fractions having same denominator are subtracted then only numerators are subtracted, denominator remains unchanged.

So, the given expression can be simplified as,

  715215=7215715215=515

Now,

  5 can be written as the product of 5 and 1.

  15 can be written as the product of 5 and 3.

So, 515 can be further simplified as,

  515=5×15×3

Striking off the common terms, we get,

  515=13

Hence, the simplified form of 715215 is 13 .

Chapter 0 Solutions

Algebra 1

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