Which of the following mRNA sequences codes for the polypeptide sequence tyrosine-leucine-alanine? Group of answer choices 5’-UACCUAGCU-3’ 5’-GUGCAAUUU-3’ 5’-AUGGUAACA-3’ 5’-GGUCGCCAU-3’
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- The following segment of DNA codes a protein. The uppercase letters represent Exons, the lowercase letters introns. Draw the pre- mRNA, the mature mRNA and translate the codons using the genetic code to form the protein. Identify the 5’UTR and 3UTR 5’- AGGAAATGAAATGCCAgaattgccggatgacGGTCAGCaatcgaGCACATTTGTGATTTACCGT-3’The DNA sequence below is transcribed from left to right (the partner/coding strand is shown). Using this sequence, write the sequence of the polypeptide that results from this gene. Be sure to appropriately label the ends of the molecule. 5'-ATGCACGGCGACTAG-3' Second letter A UAU Tyr UAC First letter U A G U UUU1 UUC UUA LOU Leu CUU CUC CUA CUG Phe GUU GUC GUA GUG Leu AUU AUC lle AUA AUG Met Val C UCU UCC UCA UCG CCU CCC CCA CCG ACU ACC ACA ACG GCU GCC GCA GCG Ser Pro Thr Ala CAU His CAC CAA CAG Gin AAU Asn AAC AAA 1 Lys AAG LYS G {}a UAA Stop UGA Stop A UAG Stop UGG Trp GAU 1 GAC Asp GAA GIU Glu GAGJ UGU UGC CGU CGC CGA CGG AGU AGC AGA AGG Cys GGU GGC GGA GGG Arg Ser Arg DOA DOA DOA DUTO Third letter GlyConsider the following mature mRNA from a human cell: 5' UAAUGUCGCAAUAACC 3¹ What is the sequence of amino acids in the translated protein? Second letter A First letter С U d A G บบบ UUC P U UUA UUG Leu CUU CUC CUA CUG GUU GUC GUA GUG -Phe Met-Ser-Gln Met-Arg-Lys-Ser Leu Stop-Cys-Arg-Asn-Asn C AUU AUC lle AUA ACA AUG Met ACG Val UCU UCC UCA UCG CCU CCC CCA CCG ACU ACC GCU GCC GCA GCGJ Ser Pro Thr Ala UAU UAC Tyr UGU UGC. UAA Stop UGA Stop UAG Stop UGG Trp CAC CAGGin CAU His Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. AAU Asn AAA Lys AAG. There is no start codon, resulting in no translated protein. GAU ASP GAC Glu GAA GAG G CGU CGC CGA CGG Cys AGU AGC AGA AGG Arg GGU GGC GGA GGGJ Arg ser Gly MCAG U UCAG с А SCAG U SCAG U Third letter
- What is the sequence of the mRNA transcript that will be produced from the following sequence of DNA? The top strand is the template strand, the bottom strand is the coding strand. 5’ – TCGGGATTAGACGCACGTTGGCATACCTCG – 3’ 3’ – AGCCCTAATCTGCGTGCAACCGTATGGAGC – 5’ Enter the mRNA sequence here (pay close attention to the direction of the molecule!): 5'-_____-3'A mRNA sequence is shown below. Note that the coding strand of DNA has the same sequence as the mRNA, except that there are U’s in the mRNA where there are T’s in the DNA. The first triplet of nucleotides AAU (underlined) is in frame for coding, and encodes Asparagine. 45 50 55 60 65 5’—A A C G A A U C G U C G C C A A C U A A G A G –-3’ Which of the following DNA mutations is almost certain to result in a shorter than normal protein? at position 56 a change from G to C an insertion of a G after the G at position 56 inversion of region 56-59 (G C C A) an delete the C at position 52 None of the above.A protein uses a gene template in 3' to 5' direction. What are the amino acid sequences following this DNA chain? 5'-ATGTCGACAGCCTAA-3' First Second Letter Third Letter Letter phenylalanine phenylalanine serine tyrosine tyrosine cysteine cysteine U serine leucine serine stop stop A leucine serine stop tryptophan arginine G leucine proline histidine leucine proline histidine arginine leucine proline glutamine arginine arginine A leucine proline glutamine isoleucine threonine asparagine asparagine lysine serine isoleucine threonine serine A isoleucine threonine arginine methionine threonine lysine aspartate arginine valine alanine glycine glycine valine alanine aspartate C G valine alanine glutamate glycine glycine A valine alanine glutamate O Met-lle-Thr-Ala-STOP O Met-Ser-Trp-Arg-STOP O Met-Tyr-Thr-Arg-STOP O Met-Ser-Thr-Ala-STOP
- Table 8.2: Transcription and translation of the first 7 codons in the B-globin chain of hemoglobin. Normal Sequence Mutated Sequence DNA DNA amino acid DNA DNA amino Codon MRNA Codon MRNA coding template strand coding template strand strand acid code code strand sequence sequence G 1 1 G G C 2 A 2 A 3 G G A A 4 4 C G A G G G G 7 A 7 A G G Shape of RBC Shape of RBC 23 3.A protein uses a gene template in 3' to 5' direction. What are the amino acid sequences following this DNA chain? 5'-ATGTCGACAGCCTAA-3' First Second Letter Third Letter U A G Letter phenylalanine serine tyrosine cysteine U phenylalanine serine tyrosine cysteine U leucine serine stop stop A tryptophan arginine arginine leucine serine stop leucine proline histidine U leucine proline histidine leucine proline glutamine arginine A leucine proline glutamine arginine G isoleucine threonine asparagine serine U isoleucine threonine asparagine serine A isoleucine threonine lysine arginine A methionine threonine lysine arginine G valine alanine aspartate glycine U valine alanine aspartate glycine G valine alanine glutamate glycine A valine alanine glutamate glycine G O Met-lle-Thr-Ala-STOP O Met-Ser-Thr-Ala-STOP Met-Ser-Trp-Arg-STOP Met-Tyr-Thr-Arg-STOPFor each of the following items, fill in either the DNA strand, the MRNA codons, the tRNA anticodons, or the amino acid sequence that have been left blank. If several sequences might work, choose only one. Furthermore, circle the start and the stop codons of each mRNA sequence. 1. DNA (3'-5') ACG TAC GGC CGG TTA AAG CAT ACT TTC TTG MRNA TRNA Amino Acid 2. DNA (3'-5') MRNA AUG ACU AGC UGG GGG UAU UAC UUU UAG AAA TRNA Amino Acid 3. DNA (3'-5') MRNA TRNA GCU CCU UAC CAC ССС CGU AUG GCU GGG AUC Activate Go to Sett Amino Acid
- You may wish to consult the genetic code above to answer the following question. A mutation has changed a portion of a protein coding gene that encodes a messenger RNA sequence. The original messenger RNA sequence is 5'-AUGCCCAGAGCU-3' Which mutation is a frameshift mutation that changes all of the amino acids that follow the changed sequence? O 5-AUGCCCUGAGCU-3' 05-AUGCCCCAGAGCU-3" 05-AUGCCCACAGCU-3" 05 AUGCCCAGGGCC-3"If DNA segments changes from GCATAG to GCATA, this is a: MRNA Codon/Amino Acid Chart First Base Second Base Third Base U A G 0001 Phenylalanine UCU UAU1 Tyrosine (Tyr) UAC UGUT FCcysteine (Cys) UGCJ U UUCJ (Phe) UCC Serine (Ser) UCA U UUA1 UAAT UGA - Stop A FLeucine (Leu) UUG- FStop UAG- UCG- UGG - Tryptophan (Trp) G CU- CCU CGUT CAU1 Histidine (His) CAC U CUC FLeucine (Leu) CUA CC Proline (Pro) CCA CGC FArginine (Arg) CGA CAA1 Glutamine A CAGI (Glu) CGG- CUG- CCG- G AUU AAU1 Asparagine ACU1 AGUT FSerine (Ser) AGC- AUC FIsoleucine (le) ACC Threonir AACJ (Asn) A AUA- ACA (Thr) AAA1 FLysine (Lys) AAG- AGA, FArginine (Arg) AGG- A Start Methionine (Met) ACG- AUG - GUU- GCU GAU- GGU | Aspartic Acid GAÇJ(Asp) U GỤC Valine (Val) GUA GCC FAlanine (Ala) GGC Glycine (Gly) GGA G GAA1 Glutamic Acid A GCA GCG- GAGJ (Glu) GGG- GUG- GThe sequence of part of an mRNA transcript is What is the sequence of the DNA coding strand? 5'- 5' - AUGGGGAACAGCAAGAGUGGGGCCCUGUCCAAGGAG - 3' 5'- ATGGGGAACAGCAAGAGTGGGGCCCTGTCCAAGGAG What is the sequence of the DNA template strand? TACCCCTTGTCGTTCTCACCCCGGGACAGGTTCCTC Incorrect -3' -3'
