College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- What is your weight 600 km above the surface of Venus, assuming that the acceleration due to gravity on the surface of Venus is 8.875 m/s2 and that your mass is 90 kg?arrow_forwardIf you weigh 685 N on the earth, what would be your weight on the surface of a neutron star that has the same mass as our sun and a diameter of 18.0 km ? Take the mass of the sun to be ms = 1.99×1030 kg , the gravitational constant to be G = 6.67×10−11 N⋅m2/kg2 , and the acceleration due to gravity at the earth's surface to be g = 9.810 m/s2 . Express your weight wstar in newtons.arrow_forwardWhat is the escape speed from a planet of mass M = 3.1 x 1023 kg and radius R = 2.6 x 106 m? Write the answer in terms of km/s.arrow_forward
- Comets travel around the sun in elliptical orbits with large eccentricities. If a comet has speed 3.1x10^4 m/s when at a distance of 2.7x10^11 m from the center of the sun, what is its speed when at a distance of 4.7x10^10 m? Mass of the Sun is 1.99×10^30 kg. Gravitational constant is G=6.67×10^(−11) m^3 /(kg⋅s). What is the formula? (Answer: 75006.70209088 m/s)arrow_forwardYou encounter a strange cosmic string in outer space. The string extends along the x axis from x = 0 m to x = 4.6 x 104 m. You are located at x = -5.4 x 104 m. You experience a gravitational field equal to 9.6 x 10-6 N/kg at this location. Assuming the string has a constant linear mass density, calculate this linear mass density, in units of 105kg/m. Use G = 6.7 x 10-11 N m2/ kg2. (Please answer to the fourth decimal place - i.e 14.3225)arrow_forwardDetermine the gravitational field at mass A. The radius of masses A and C is 50 cm while the radius of mass B is 75 cm.arrow_forward
- Find the distance of a point from the earth's center where the resultant gravitational field due to the earth and the moon is zero. The mass of the earth is 6 * 0 * 10 ^ 24 kg and that of the moon is 7*4*10^ 22 kg. The distance between the earth and the moon is 4*0*10^ 5 km.arrow_forwardConcern the planet Mars, which has a radius of 3400 km. On Mars, the acceleration due to gravity is 3.72 m/s^2 The mass of the sun is 2.0×1030 kg, while the (actual) mass of Mars is 6.4×1023 kg. The average distance from Mars to the sun is 228 million kilometers. a. What is the gravitational force acting on Mars due to the sun? What is the reaction force to this force? Name or explain the force; don’t give a value. b. What are the speed and angular velocity of Mars? Compare the values to those of Earth. c. Using only information provided above, estimate the length of a year on Mars. Compare the value to that of Earth.arrow_forwardDuring a solar eclipse, the Moon is positioned directly between Earth and the Sun. The masses of the Sun, Earth, and the Moon are 1.99 × 10³0 kg, 5.98 × 1024 kg, and 7.36 × 1022 kg, respectively. The Moon's mean distance from Earth is 3.84 × 108 m, and Earth's mean distance from the Sun is 1.50 × 10¹¹ m. The gravitational constant is G = 6.67 × 10-¹1 N-m²/kg². Find the magnitude F of the net gravitational force acting on the Moon during the solar eclipse due to both Earth and the Sun. F = What is the direction of this force? toward Earth toward Venus toward the Sun elsewhere Narrow_forward
- You are trapped on an earth-like planet with a mass of 7.00×1024 kg and a radius of 3000 km. You were able to build a cannon capable of launching a human. What velocity will you need to escape the planet? (We can simplify the Gravitational Constant G to 6.7x10-11 Nm2/kg) m/sarrow_forwardA 4.00 x 10^8 kg mass and 5.00 x 10^8 kg mass are separated by a distance of 2.0 km. What is the gravitational force of attraction between the masses?arrow_forwardWhat is the gravitational acceleration on the surface of the Sun? The mass of the Sun is 1.99×1030kg. The radius of the Sun is 6.97×108m. The universal gravitational constant is 6.67×10−11N⋅m2/kg2arrow_forward
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