Find the distance of a point from the earth's center where the resultant gravitational field due to the earth and the moon is zero. The mass of the earth is 6 * 0 * 10 ^ 24 kg and that of the moon is 7*4*10^ 22 kg. The distance between the earth and the moon is 4*0*10^ 5 km.

Compare the magnitude of the gravitational field at the surface of the earth due to the moon with that due to the sun. (Hint: The mass of the sun is 1.99 x 10^30 kg, the mass of the moon is 7.36 x 10^22 kg, and the distance from the surface of the earth to the moon is 3.78 10^8 m.)

(A) Find the magnitude of the gravitational force (in N) between a planet with mass 7.75 ✕ 1024 kg and its moon, with mass 2.35 ✕ 1022 kg, if the average distance between their centers is 2.20 ✕ 108 m.     (B) What is the moon's acceleration (in m/s2) toward the planet? (Enter the magnitude.) m/s2     (C) What is the planet's acceleration (in m/s2) toward the moon? (Enter the magnitude.) m/s2

During a solar eclipse, the Moon is positioned directly between Earth and the Sun. The masses of the Sun, Earth, and the Moon are 1.99×10^30 kg, 5.98×10^24 kg, and 7.36×10^22 kg, respectively. The Moon's mean distance from Earth is 3.84×10^8 m, and Earth's mean distance from the Sun is 1.50×10^11 m. The gravitational constant is G=6.67×10^−11 N·m2/kg^2. Find the magnitude F of the net gravitational force acting on the Moon during the solar eclipse due to both Earth and the Sun.

The gravitational constant G was first measured accurately by Henry Cavendish in 1798. He used an exquisitely sensitive balance to measure the force between two lead spheres whose centers were 0.27 m apart. One of the spheres had a mass of 168 kg, while the mass of the other sphere was 0.73 kg. What was the ratio of the gravitational force between these spheres to the weight of the lighter sphere?

Scientists want to place a 4 × 103 kg satellite in orbit around Mars. They plan to have the satellite orbit at a speed of 2330 m/s in a perfectly circular orbit. Here is some information that may help solve this problem: mmars = 6.4191 x 1023 kgrmars = 3.397 x 106 mG = 6.67428 x 10-11 N-m2/kg2 1.)Which of the following quantities would change the radius the satellite needs to orbit at? a.)the mass of the satellite b.)the mass of the planet c.)the speed of the satellite   2.)What should the speed of the orbit be, if we want the satellite to take 8 times longer to complete one full revolution of its orbit?

A mountain located 10.0 km from a person exerts a gravitational force on them equal to 3.00% of their weight. The gravitational constant ? is 6.67×10−11m3/(kg·s2), and the acceleration due to gravity ? at the surface of the Earth is 9.81 m/s2. Calculate the mass ? of the mountain.

What is the ratio of the sun's gravitational pull on Mercury to the sun's gravitational pull on the earth? The radius of the orbit of Mercury is RM=5.79×1010mRM=5.79×1010m and its mass is mM=3.30×1023kgmM=3.30×1023kg. The radius of the orbit of Earth is RE=1.50×1011mRE=1.50×1011m and its mass is mE=5.97×1024kgmE=5.97×1024kg. FM/FE=

A satellite m = 500 kg orbits the earth at a distance d = 199 km, above the surface of the planet. The radius of the earth is re=6.38×106 m and the gravitational constant G =6.67×10-11 N m2/kg2 and the Earth's mass is me=5.98×1024 kg. What is the speed of the satellite in m/s?

Two objects attract each other with a gravitational force of magnitude 1.02  10-8 N when separated by 19.8 cm. If the total mass of the two objects is 5.06 kg, what is the mass of each?