Uo 10 R1 R2 12 A IL V UL RL U₁ = 6 V R1 = 100 Ω R₂ = 33 R1 = 1 Ω ... 1 ΚΩ

hand written asap plzzzzz..i'll upvote

Quèstion 14 Power supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to L-Dc こosA 22V rmsら 50H2 RL VL-DC =20V 7. 0.01 F 0.02 F 0.0167 F None of the above

Construct a forward bias diode circuit in multi-sim (desktop, not live). Simulate and find the current through the resistor and the voltage across the resistor.

VCC V1 D2 .tran 10 QTLP690C R8 1k Q4 2N2222 R6 1k vout Q2 2N2222 R2 470 R4 56k C2 47μ VCC C1 47μ Astable Multivibrator R3 56k w R1 470 Q1 2N2222 R5 1k D1 QTLP690C R7 1k Q3 2N2222 How many states does this circuit have? Draw a circuit diagram showing each state.

The circle is below(for D1-1N4148 is 1N4148 Diode).  and also there have a table(. Note that the first 3 rows of measurement are obtained when the diode is reverse-biased) Vout_dc (V) VD (V) ID (μA) 0.51 -0.51 0.0 0.23 -0.20 0.0 0.10 -0.08 0.0 0.00 0.00 0.0 0.05 0.04 0.0 0.11 0.09 0.0 0.17 0.15 0.1 0.19 0.20 0.1 0.27  0.25 0.4 0.32 0.30 1.6 0.36 0.34 3.1 0.42 0.40 8.2 0.46 0.42 14.3 0.52 0.47 28.0 Questions: 1)  plot the diode’s I-V characteristics on a linear scale (ID on the y-axis and VD on the x-axis)  2)  [RP4] 3)  [RP5]

2x 1N4148 2,2K R = 1K V=12Vp 2,2K Please find and draw the voltage over the load resistance, RL. Hint: 1N4148 is a Si-based diode. You have to show all the calculation details and verbal explanations. You can prepare your answer on paper with hand-written and name&ID on the top right corner of each paper. You can email your scanned answer with enough explanatory details of your name, ID, and exam title.

This is a practice question from my Introduction to Electronics course. Could you please walk me through the process of solving this so that I can figure out more complex circuits? Thank you for your assistance.

I need answer ASAP If you solve it i will give you one big like

I have a half size breadboard,9V source, multimeter, 220 resistor, (forward biased) 1N914 diode, in series.  Im reading about 9.7mA. The simulation reads close to 36mA. Can you help me to figure out if I am doing something wrong. (I lfet the battery a little unhooked so the resistor would not overheat). This image shows how I set up my circuit I need to read current first than volage the simulation  has another multimeter we are to relace with a jumper wire to read voltage of the diode. We first must read circuit currrent.