Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN: 9781305632134
Author: J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher: Cengage Learning
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- Explain this diagramarrow_forwardShown in the figure below is an electrical circuit containing three resistors and two batteries. I₁ 0= 4 + L . ww R3 R₂ ww 1₂ R₁ ww Write down the Kirchhoff Junction equation and solve it for I, in terms of I₂ and I3. Write the result here: 1₁ = 12-13 R₂=552 R₂ = 132 13 Write down the Kirchhoff Loop equation for a loop that starts at the lower left corner and follows the perimeter of the circuit diagram clockwise. - IzR3 − LR₁ + 14 + 10 Write down the Kirchhoff Loop equation for a loop that starts at the lower left corner and touches the components 4V, R₂, and R₁. 0 = 4-1₂R₂-11R₁ The resistors in the circuit have the following values: R₁ = 12 Solve for all the following (some answers may be negative): I₁ = 27.78 X Amperes 1₂ = 28.84 X Amperes 13 = 1.060 X Amperes NOTE: For the equations, put in resistances and currents SYMBOLICALLY using variables like R₁,R₂,R3 and 11,12,13. Use numerical values of 10 and 4 for the voltages.arrow_forwardConsider the series-parallel circuit shown in the figure below with various multimeters connected in the circuit. Assum that XMM1 has been configured in ammeter mode, and XMM2 has been configured in voltmeter mode. XMM1 R1 1kQ XMM2 R2 R3 V1 1kQ 1kQ 12V 3.1: Redraw the circuit replacing XMM1 and XMM2 by their equivalent circuit models 3.2: Assume that XMM2 was incorrectly configured in ammeter mode. Redraw the equivalent circuit from 3.1 and compute the current that would be measured by the ammeter in this scenario. Hil-arrow_forward
- (e) Create a list of components for the following circuit. 6v Vcc D1 R7 4k7 ZS D2 ( M RV1 470k C1 100nF 10µF C2 IC1 R2 150k RS Q4 Q5 Q4-Q14 R5 Q1 Q6 4. Q7 4k7 10 14 13 15 RTC Q8 Q9 4060 Q10 Q12 Q13 Q14 стс R1 100k _12 MR R4 4.7k R6 4.7k LED1 LED2arrow_forwardjulSjrpjdLjcwDWXZoojA9XtU12Mi-pTxteUKH * In the circuit of figure below, v() is 7 V-4 ww 10 V () = 7F True False * In figure below, Vab=7 V in case (b) -5 5 V 5 V 5 V S V 3 V 3 V 3 V 3 V 1 V 1V 1V (a) (b) (c) (d) True Falsearrow_forwardPlease someone help me to slove these two problems, and give me an explanation , thank youarrow_forward
- Solve for the Thevenin voltage (Vth) of fhe circuit below.arrow_forwardUsing the supernode concept to determine the voltage marked v20 in the figure, the crossed wires that are not marked by a thick dot are not in physical contact.arrow_forwardOCX elp VCC VEE 6V 3V R2 A R1 2kQ 2kQ R5 2kQ a) Find the voltage at point A due to VCC only. b) Find the voltage at point A due to VEE only. c) Find the voltage at point A when both are activated.arrow_forward
- (d) For the circuit shown in Figure Q1(d), the inductors have the following value: L1 = 1 mH, L2 = L3 = 2 mH, L4 = 5 mH, and L5 = L6 = 4 mH. Calculate the total inductance as seen from: (i) Terminals a-b (ii) Terminals b-carrow_forwardR, =3.3 k2 R -1 k2 R: =2.2 ks2 R =470 2 V, 12VT a a) ldentify all nodes and label knoun and unknoLn voltage) b) Use onms law (al= Vrrom- Vto) %3D andkeL to derive equation for each ode an With unkno un voltage. an c) SoIve the equetionsarrow_forwardD. Find g12. Express your answer using three significant figures.arrow_forward
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ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:Cengage Learning