The tallest spot on Earth is Mt. Everest, which is 8850 m above sea level. If the radius of Earth to sea level is 6359 km, how much does the gravitational field strength change between the sea level value at that location (9.826 N/kg) and the top of Mt. Everest?

What is the gravitational field intensity at a distance of 8.4 x 107 m from the centre of Earth?

Consider that the Moon was exactly aligned with the Earth and the Sun, and that it will be located between both celestial bodies. What is the ratio between the magnitude of the gravitational force exerted by the Earth on the Moon (FTL) and the respective force exerted by the Sun on the Moon (FSL), i.e. FTL/FSL? Note: M Sun = 1.99 x 10 30 kg, M Earth = 5.97 x 1024 kg and M Moon = 7.35 x 10 22 kg. The Earth- Moon distance is 3.84 x10° m and the Earth-Sun distance is 1.50 x 10 11 m. a. 2.2 b. 0.46 c. Ninguna de las propuestas es correcta. -3 d. 1.2 x 10 e. 8.5 × 10

The mass of planet X is 6.4 x 1023 kg and the aceleration of gravity on its surface is 3.7 m/s², if the gravitational constant G = 6.67 x 10-11 N.m²/kg², the radius of this planet R is a) 3.40 x 106 m c) 4.03 x 106 m e) 1.15 x 1013 m b) 2.98 x 106 m d) 7.56 x 106 m.

Consider a spherical shell constructed from a material of density 6.1 x 103 kg/m3.  The inner radius of the shell is 4.9 x 106 m from the center, and the outer radius of the shell is 9.2 x 106 m from the center.  Calculate the magnitude of the gravitational field 13.1 x 106 m from the center of the shell, in N/kg.  Use G = 6.7 x 10-11 N m2 / kg2. (Please answer to the fourth decimal place - i.e 14.3225)

The gravity on the Moon is equal to 20.52 meters per second squared. During the battle between Alice and Fernanda, Alice was victorious because Fernanda was unable to lift Claudia's hammer, which had been placed in the Moon by Steph after Claudia was murdered by Steph. If Alice is worthy, but she can only lift Claudia's hammer 0.8 meters above the ground on the moon, how high can Alice lift the hammer if the fight takes place on earth?

Every few months, memes circulate claiming that certain alignments of the planets with the Earth will result in a change in the gravitational force you feel. Usually these memes state that the alignment will counteract Earth's gravity slightly so you will feel less of a gravitational pull towards the Earth. Can this ever happen? Let's look at the numbers. What is the gravitational force (in N) of the Earth on you (MĚ = 5.97 × 1024 kg, R₁ = 6380 km)? Say your mass is 64 kg. (Enter the magnitude.) What is the gravitational force (in N) of Jupiter on you when it is closest to Earth (M₁ = 1.90 × 1027 kg, R₁ = 5.88 × 108 km)? (Enter the magnitude.) By what factor would the mass of Jupiter need to increase to be equal to the gravitational force you feel from the Earth? Part 1 of 5 The gravitational force between two masses is given by -GMm r² where G = 6.67 x 10-11 m³/s²/kg. FgE Part 2 of 5 We can use this expression to determine the magnitude of the gravitational force you feel while on the…

The International Space Station (ISS) completes one orbit of Earth in 92 minutes.  What is the radius of the orbit in kilometers (km)?    You may assume the orbit is circular.  The mass of the ISS is 420 kg, and the mass of the Earth is 6.0×10246.0×1024kg.  Newton’s gravitational constant is 6.7×10−11N⋅m2kg26.7×10−11kg2N⋅m2​.

You encounter a strange cosmic string in outer space.  The string extends along the x axis from x = 0 m to x = 4.6 x 104 m.  You are located at x = -5.4 x 104 m.  You experience a gravitational field equal to 9.6 x 10-6 N/kg at this location.  Assuming the string has a constant linear mass density, calculate this linear mass density, in units of 105kg/m.  Use G = 6.7 x 10-11 N m2/ kg2. (Please answer to the fourth decimal place - i.e 14.3225)

Determine the gravitational field at mass A. The radius of masses A and C is 50 cm while the radius of mass B is 75 cm.