The program below reads two integers. Then a function with the following prototype is called:                              void div_rem(int a, int b, int *divides, int *remains); This function is passed the two integers. It divides them (using integer division), and writes the answer over wherever “divides” points. Then it finds the remainder and writes it into where “remains” points. Thus for 20 and 3, 20 divided by 3 is 6, remainder 2. Implement the div_rem function.  #include void div_rem(int a, int b, int *divides, int *remains);  int  main(void)

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
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Question 3
The program below reads two integers. Then a function with the following
prototype is called:

                             void div_rem(int a, int b, int *divides, int *remains);

This function is passed the two integers. It divides them (using integer division),
and writes the answer over wherever “divides” points. Then it finds the
remainder and writes it into where “remains” points. Thus for 20 and 3, 20
divided by 3 is 6, remainder 2. Implement the div_rem function. 

#include <stdio.h>
void div_rem(int a, int b, int *divides, int *remains); 

int  main(void) 

{

               int a, b;  
               int div = 0;
               int rem = 0; 

printf("enter two integers ");
scanf("%i %i", &a, &b);

div_rem(a, b, &div, &rem); 

printf("%i divided by %i = %i "
             "remainder %i\n", a, b, div, rem); 

return 0;
}

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