7.18 LAB: A jiffy A jiffy" is the scientific name for 1/100th of a second. Define a function named JiffiesToSeconds that takes a float as a parameter, representing the number of "jiffies", and returns a float that represents the number of seconds. Then, write a main program that reads the number of jiffies as an input, calls function JiffiesToSeconds() with the input as argument, and outputs the number of seconds. Output each floating-point value with three digits after the decimal point, which can be achieved as follows: printf("%0.31f\n", yourValue); Ex: If the input is 15.25 the output is 0.152 The program must define and call a function: double JiffiesToSeconds (double userJiffies) LAB 718.1 LAB: Ajiffy 0/10 ACTIVITY Load default template. 1 #include 2 3/ Define your function here / A 5 int main(void) ( 6 main.c

Coding language: Java

What are the propagation time and the transmission time for an 8-Mbyte message (an image) if the bandwidth of the network is 1 Mbps? Assume that the distance between the sender and the receiver is 14,000 km and that light travels at 2.4 x 108 m/s. (7) (ii) Discuss any two network impairments? (3)

import java.util.Scanner ; //This program enables the user enters 10 int between -100 and 100 //then a menu is presented to the user to choose an operation to be //performed on the entered numbers. //operations: add all numbers and display their total //display the average of the numbers //find and display all negative numbers //find and display odd numbers //display all numbers in reverse order //display all 5 multiples public class OPonArrays { public static void main (String [] main) { int SIZE = 10; int [] nums= new int [SIZE]; Scanner KB = new Scanner(System.in); // populate the array for(int i = 0; i < 10; i++) { System.out.println("please enter a number between -100 and 100"); nums[i] = KB.nextInt(); } //display all elments for(int i = 0; i < 10; i++) { System .out.println(nums[i]); } fix the error