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The nicotine content in cigarettes of a certain brand is normally distributed. The brand advertises that the mean nicotine content of their cigarettes is µ = 1.5, but measurements on a random sample of 100 cigarettes of this brand gave a mean of ?̅= 1.53 and s = 0.95. Is this evidence that the mean nicotine content is actually higher than advertised? 1. State the appropriate null and alternative hypotheses. H0: ? = 1.5 Ha: ? > 1.5 2. Should you use the z or t test? t – do not have sigma 3. Compute the test statistic to test your hypotheses. (report to 2 decimal places) ? = 1.53−1.5 0.95 √100 ⁄ = 0.32 4. Find the appropriate range of p-value for your test. P-value:  a. Less than 0.005 b. Between 0.005 and 0.01 c. Between 0.01 and 0.025 d. Between 0.025 and 0.05 e. Greater than 0.05

The nicotine content in cigarettes of a certain brand is normally distributed. The brand advertises that the mean nicotine content of their cigarettes is µ = 1.5, but measurements on a random sample of 100 cigarettes of this brand gave a mean of ?̅= 1.53 and s = 0.95. Is this evidence that the mean nicotine content is actually higher than advertised? 1. State the appropriate null and alternative hypotheses. H0: ? = 1.5 Ha: ? > 1.5 2. Should you use the z or t test? t – do not have sigma 3. Compute the test statistic to test your hypotheses. (report to 2 decimal places) ? = 1.53−1.5 0.95 √100 ⁄ = 0.32 4. Find the appropriate range of p-value for your test. P-value:  a. Less than 0.005 b. Between 0.005 and 0.01 c. Between 0.01 and 0.025 d. Between 0.025 and 0.05 e. Greater than 0.05

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter1: Fundamental Concepts Of Algebra
Section1.4: Fractional Expressions
Problem 65E
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The nicotine content in cigarettes of a certain brand is normally distributed. The brand advertises that the mean nicotine content of their cigarettes is µ = 1.5, but measurements on a random sample of 100 cigarettes of this brand gave a mean of ?̅= 1.53 and s = 0.95. Is this evidence that the mean nicotine content is actually higher than advertised?

1. State the appropriate null and alternative hypotheses.

H0: ? = 1.5

Ha: ? > 1.5

2. Should you use the z or t test?

t – do not have sigma

3. Compute the test statistic to test your hypotheses. (report to 2 decimal places)

? = 1.53−1.5 0.95 √100 ⁄ = 0.32

4. Find the appropriate range of p-value for your test. P-value: 

a. Less than 0.005

b. Between 0.005 and 0.01

c. Between 0.01 and 0.025

d. Between 0.025 and 0.05

e. Greater than 0.05

Area = 0.05 Area = 0.025 Area = 0.01 Area = 0.005 -1.660 -2.626 -1.984 -2.364 0 +1.660 +1.984 Area = 0.05 Area = 0.025 +2.364 Area = 0.01 Area = 0.005 +2.626
Transcribed Image Text:Area = 0.05 Area = 0.025 Area = 0.01 Area = 0.005 -1.660 -2.626 -1.984 -2.364 0 +1.660 +1.984 Area = 0.05 Area = 0.025 +2.364 Area = 0.01 Area = 0.005 +2.626
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