The first parts of the stress-strain relationships of the components of a randomly oriented composite are shown in Figure P11.25. Estimate the volume percentage of fibers in the composite assuming a fiber efficiency parameter (K) of 0.2. 1400 1200 1000 - 800 E Fibers 600 - Composite 400 200 Matrix 0.002 0.004 0.006 Strain (m/m) FIGURE P11.25 Stress (MPa)
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- The first parts of the stress-strain relationships of the components of a randomly oriented composite are shown in Figure P11.25. Estimate the volume percentage of fibers in the composite assuming a fiber efficiency parameter (K) of 0.2. Stress (MPa) 1400 1200 1000 800 600 400 200 I T FIGURE P11.25 0.002 Fibers Strain (m/m) 0.004 Composite Matrix 0.006The first parts of the stress–strain relationships of the components of a randomly oriented composite are shown in Figure P11.25. Estimate the volume percentage of fibers in the composite assuming a fiber efficiency parameter (K) of 0.2.The load-strain data obtained in a tension test of a unidirectional carbon fiber/epoxy composite are given below. The specimen dimensions are length=254 mm, width=12.7 mm and thickness is 1.4 mm. Determine the tensile modulus and Poisson ration for each fiber orientation Axial strain Load (N) Transverse strain % 自 % 0° 45° 90° 0° 45° 90° 0.05 2130 130 67 -0.012 -0.113 -0.0004 0.10 4270 255 134 -0.027 -0.021 -0.001 0.15 6400 360 204 -0.041 -0.029 -0.0014 0.20 8620 485 333 -0.054 -0.038 -0.0019 0.25 565 396 -0.048 -0.0025
- Determine the maximum moment of inertia of the composite figure shown below, in mm^4.O 9:r. Q.2.jpg → Q.2. For the composite bar shown in Fig. 2, find the total deformation in x and y directions due to the applied load and change in temperature (drop) of 80°C, knowing that (Es 208 kN/mm?, E = 75 kN/mm?, a, = 11.7*106 mm/mm.°C, a A = 23*106 mm/mm.°C, µ,=0.29 and H=0.25. D=200 mm Steel Aluminum 150 kN 150 kN 1.5m 1.5 m Fig. 2 IICalculate the modulus of elasticity of fiberglass under isostrain condition if the fiberglass consists of 70% E-glass fibers and 30% epoxy by volume. Also, calculate the percentage of load carried by the glass fibers. The moduli of elasticity of the glass fibers and the epoxy are 70.5 and 6.9 GPa, respectively. If a longitudinal stress of 60 MPa is applied on the composite with a cross-sectional area of 300 mm2, what is the load carried by each of the fiber and the matrix phases?What is the strain sustained by each of the fiber and the matrix phases?
- PROBLEM 6.56 50 mm A steel bar and an aluminum bar are bonded together as shown to form a composite beam. Knowing that the vertical shear in the beam is 18 kN and that the modulus of elasticity is 200 GPa for the steel and 73 GPa for the aluminum, determine (a) the average stress at the bonded surface, (b) the maximum stress Aluminum 25 mm Steel in the beam. 36 mmProblem # 2: For the composite area shown, calculate the moment of inertia about X and Y ахes. 95 mm Ŕ = 60 mm 55 mm 35 mm 70 mm 80 mm 125 mmIV- It is necessary to design a continuous and aligned glass fiber-reinforced polyester having a tensile strength of at least 1400 MPa in the longitudinal direction. The maximum possible specific gravity is 1.65. Using the following data, determine whether such a composite is possible. Justify. Assume a value of 15 MPa for the stress on the matrix when the fibers fail. Material Glass fiber Polyester Specific gravity 2.5 1.35 Tensile strength (MPa) 3500 50
- Determine the y-bar centroid of the composite figure shown. Where x1=69; x2=100 and y=88A short reinforced concrete column is subjected to a 600 kips axial compressive load. The moduli of elasticity of plain concrete and steel are 5 * 106 psi and 30 * 106 psi, respectively, and the cross-sectional area of steel is 1.8% of that of the reinforced concrete. Considering the column as a structural member made of a composite material and subjected to load parallel to the steel rebars, calculate the following:a. the modulus of elasticity of the reinforced concreteb. the load carried by each of the steel and plain concretec. the minimum required cross-sectional area of the column, given that the allowable compressive stress of plain concrete is 5000 psi and that the allowable compressive stress of plain concrete will be reached before that of steelQ3A/ Composite of concrete rainforced by steel rods of 20%, modulus elasticity of concrete 30 Mpa , and modulus elasticity of steel 7 times of concrete Caculate Ec at the following coditions : 1.apllied load parallel to steel rods 2. applied load perpendicular to steel rods 3. apllied load at 45 ° to steel rods ( sin 45 =0.707 , cos 45 =0.707)