The exons and introns of a gene are shown below. Introns are shown as black bars. Exons are numbered white boxes. "nt" is abbreviation for nucleotides. For exon 1, the number of nucleotides labeled in the figure only include the sequence from the start codon to the 3' end of the exon. For exon 5, the number of nucleotides labeled in the figure only include the sequence from the 5' end of exon 5 to the stop codon. In each case, the number of nucleotides does include the start or the stop codon itself. Stop codon Start codon 4. 50 nt 150 nt 180 nt I Alternative splicing of this gene produces removes introns and joining different exons. Four different mRNA transcripts are formed by alternative splicing. All four transcripts utilize the same start codon (in Exon 1) and the same stop codon (in Exon 5) for translation. Based on this information, can you predict the exon combinations of the four transcripts and the length (l.e. number of amino acids) of each of the four proteins translated from the four transcripts? Please select all the correct answer options. 120 nt 40 nt Exons 1/4/5, length of the coding protein: 149 amino acids Exons 1/5, length of the coding protein: 99 amino acids Exons 1/2/3/5, length of the coding protein: 129 amino acids Exons 1/2/3/4/5, length of the coding protein: 179 amino acids Exons 1/2/4/5, length of the coding protein: 163 amino acids

This sequence given is of one strand of eukaryotic DNA containing a hypothetical gene. The base that is first (at the 5' end) in the sequence is at position -25. The translational start site is the first initiating codon encountered after the transcriptional start. This gene has three exons. The last base of the first exon is the A at position +30; the first base of the second exon is the C at position +62; the last base of the second exon is the A at position +82; the first base of the third exon is the G at position +118; and the last base of the third exon is for you to determine. Determine, and show, the sequence of the polypeptide produced by this gene in this format: Met-Thr-Trp-Tyr-Val etc.  5'-TATATACGTC CTATCGATGC ATCGTGTACG TAGCTAGGGG ATGCATGAAG TCACAGTAGC TAGCTATGGC TGATCGATCG TTGTGGCTTA AATATTGCGC TGGACTAGGA AAAGCTCGCA GGTACCCGAT CGATCCCGTG GAGTTCCAAG TTAGGATCTA CTTTAGCTAG TTTTAGCGGA ATAAAGATCG ATTATAGCTG AGAGATAAGC GTGGGTTGAT GATCGTAGCT AGCTAGCTAG CTAGCATCGA-3'

If the template strand of DNA carries the code: GGT-AAT-ACT, then what is the corresponding mRNA code? Recall that DNA does not use "U" as a base. Enter your answer below using the same format as shown here (three capital letters for each codon, separated by a single dash, no spaces, repeat for each codon). Table 26-1 The Genetic Code First Third Position Position (5'-end) Second Position (3'-end) U C A G Phe UAU UCU UCC Тyr Тyr Stop Stop UGU UGC Cys Cys Stop Trp UUU Ser U UUC Phe Ser UAC C UUA Leu UCA Ser UAA UGA A UUG Leu UCG Ser UAG UGG G Leu Leu Leu Leu CAU САС CAA CAG CUU CCU Pro Pro Pro Pro His His CGU Arg Arg Arg Arg U CỤC CỦA CUG CCC CCA CGC CGA C Gln Gln CCG CGG G Пе Thr ACU АСС ACA ACG AUU AAU Asn AGU Ser U AAC AAA AAG AUC Пе Thr Asn AGC Ser C AUA Ile Thr Lys Lys AGA AGG Arg Arg A A AUG* Met Thr GUU Val Val Val Val GCU GCC GCA GCG Ala GGU GGC GGA Gly Gly Gly Gly U C A GAU GỤC GUA GUG Asp Asp Glu Glu Ala GAC G Ala Ala GAA GAG GGG *AUG also serves as the principal initiation…

The following is as segment of mRNA: 5'-UCGGAAUGUGGUGGCAUACAGGCUUACAGAACUAAGUCUGAGAAU-3' A. How many amino acids long will be the protein translated from the only reading frame available in this segment? B. If a mutation changes the third letter of the stop codon in the only reading frame available in this segment, how many amino acids long will be the protein translated?

Finally, imagine that a mutation occurred in the codon below and an A was inserted between the two Ts. How would this affect the mRNA and the amino acid for that codon? Old DNA codon Old RNA codon Old amino acid New DNA codon New mRNA codon New amino acid T  T  G     T  A T  G       This would be an example of which type of a mutation?__________________________

PLEASE HELPP

draw an arrow pointing to where you would place an sgRNA(s) in order to make a full gene deletion, draw an arrow pointing to where you would place an sgRNA(s) in order to delete exon 2 draw an arrow pointing to where you would place an sgRNA(s) in order to make a single nucleotide change in exon 2

Refer to the genetic code in Figure 15.10 to answer the following question Q. If a single transversion occurs in a codon that specifies Leu, what amino acids can be specified by the mutated sequence?

The anticodon for the codon GCA is:

Write all possible codons recognized by each of the given anticodons. An anticodon strand reads 5'-UGA-3'. Fill in the missing base sequences for the possible codons recognized by the anticodon. Codon: 5- Codon: 5'- Codon: 5'- An anticodon strand reads 5'-CGA-3'. Fill in the missing base sequences for the possible codons recognized by the anticodon. Codon: 5'- -3' Codon: 5'- -3' An anticodon strand reads 5'-IAG-3'. Fill in the missing base sequences for the possible codons recognized by the anticodon. Codon: 5'- -3° ينا -3' -3'