The body temperatures in degrees Fahrenheit of a sample of adults in one small town are: 96.4 97.9 96.3 98.6 97.4 98.1 97.5 99.2 97.8 97.7 Assume body temperatures of adults are normally distributed. Based on this data, find the 95% confidence interval of the mean body temperature of adults in the town. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places. Assume the data is from a normally distributed population. 95% C.I. =

A poll was conducted that asked 1010 people how many books they had read in the past year. Results indicated that x= 10.5 books and s= 16.6 books. Construct a 99% confidence interval for the mean number of books people read. Click the icon to view the table of areas under the t-distribution. Construct a 99% confidence interval for the mean number of books people read. (Use ascending order. Round to two decimal places as needed.)

You measure 33 textbooks' weights, and find they have a mean weight of 62 ounces. Assume the population standard deviation is 4.6 ounces. Based on this, construct a 95% confidence interval for the true population mean textbook weight

A survey was conducted that asked 1009 people how many books they had read in the past year. Results indicated that x = 14.4 books and s= 16.6 books. Construct a 90% confidence interval for the mean number of books people read. Interpret the interval. Click the icon to view the table of critical t-values. C Construct a 90% confidence interval for the mean number of books people read and interpret the result. Select the correct choice below and fill in the answer boxes to complete your choice. (Use ascending order. Round to two decimal places as needed.) OA. If repeated samples are taken, 90% of them will have a sample mean between and H OB. There is a 90% probability that the true mean number of books read is between and OC. There is 90% confidence that the population mean number of books read is between and

A survey of 73 randomly selected homeowners finds that they spend a mean of $74 per month on home maintenance. Construct a 95% confidence interval for the mean amount of money spent per month on home maintenance by all homeowners. Assume that the population standard deviation is $16 per month. Round to the nearest cent.

A random sample of 64 shoppers showed that they spend an average of $27.31 per visit at the Sunday Mornings Bookstore. The standard deviation of the population is $2.14. Find the 90% confidence interval of the true mean. Please include all work showing how you found your answer.

Find 90% confidence interval

Researchers studied the mean egg length (in millimeters) for a bird population. After taking a random sample of eggs, they obtained a 95% confidence interval of (45,60). What is the value of the margin of error? Choose the correct answer below. A. 15 mm B. 52.5 mm O c. 7.5 mm O D. 1.96

Christina wants to know the true average number of pages in a typical textbook. She randomly selects 196 books, and they have an average of 161 pages. Calculate a 90.3% confidence interval if you are given that the standard deviation for a single book is 75 pages.

A survey was conducted that asked 1018 people how many books they had read in the past year. Results indicated that x = 14.3 books and s= 16.6 books. Construct a 90% confidence interval for the mean number of books people read. Interpret the interval. Click the icon to view the table of critical t-values. Construct a 90% confidence interval for the mean number of books people read and interpret the result. Select the correct choice below and fill in the answer boxes to complete your choice. (Use ascending order. Round to two decimal places as needed.) OA. If repeated samples are taken, 90% of them will have a sample mean between and OB. There is 90% confidence that the population mean number of books read is between OC. There is a 90% probability that the true mean number of books read is between and and