The accompanying diagram represents a sequence of nucleotides surrounding an RNA-coding sequence. RNA- 5'-CATGTT... TTGATGT- | coding 3'-GTACAA ... AACTACA- sequence -GACGA... TTTATA... GGCGCGC-3' |-CTGCT ... AAATAT... CCGCGCG-5'
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Which DNA strand will serve as the template strand during the transcription of the RNA-coding sequence?
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- Given the following DNA sequence of the template strand for a given gene: 5' TTTCCGTCTCAGGGCTGAAAATGTTTGCTCATCGAACGC3' Part A ) Write the mRNA that will be transcribed from the DNA sequence above (be sure to label the 5' and 3' ends). Part B ) Use the genetic code to write the peptide sequence translated in a cell from the mRNA in part A. Please use the 3 letter abbreviation for each amino acid. Part C: How would the peptide synthesized in a cell be different if the mRNA was translated in vitro (i.e. not in the cell)?Give the RNA molecule sequence transcribed from the following DNA sequence of a eukaryotic gene and with the correct 5' and 3' ends. DNA: 5'-ATAGGGCATGT-3' 3'-TATCCCGTACA-5' <--- template strand Group of answer choices 5'-ATAGGGCATGT-3' 3'-UAUCCCGUACA-5' 5'-AUAGGGCAUGU-3' 3'-TATCCCGTACA-5'The BNA sequence below is transcribed from left to right (the partner/coding strand is shown). Using this sequence, write the sequence of the polypeptide that results from this gene. Be sure to appropriately label the ends of the molecule. 5'-ATGCACGGCGACTAG-3' Second letter A UAU Tyr UAC First letter U P с > < A G U UUU UUC Phe UUA UUG CUU CUC CUA CUG L GUU GUC GUA GUG Leu Leu AUU AUC lle AUA AUG Met Val C UCU UCC UCA UCG CCU CCC CCA CCG ACU ACC ACA ACG GCU GCC GCA GCG Ser Pro Thr Ala Cys UAA Stop UGA Stop A Trp UAG Stop UGG CAC His CGU J CGC CAA I CGA Gin CAGG CGG AAA 1 AAG Lys UGU UGC AAU Asn AGC} AAC GAC Asp GAA GAGGIU For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac). BIUS Paragraph V Arial G 1 AGA 1 AGG GGU GGC GGA GGG Arg Ser Arg Gly V DCAG DCA DOA UCAG Third letter 10pt < Av V IX Q ... O WORDS POWERED BY TINY
- What is the sequence of the mRNA transcript that will be produced from the following sequence of DNA? The top strand is the template strand, the bottom strand is the coding strand. 5’ – TCGGGATTAGACGCACGTTGGCATACCTCG – 3’ 3’ – AGCCCTAATCTGCGTGCAACCGTATGGAGC – 5’ Enter the mRNA sequence here (pay close attention to the direction of the molecule!): 5'-_____-3'Assume a bacterial gene underwent a mutation, where a thymine base from an early portion of the coding sequence of the DNA is replaced with a cytosine (as illustrated below). Original sequence (coding strand): AGTTCCTACAAAATGGAGCTGTCTTGGCATGTAGTCTTT ...[Sequence continues with another 80 bases] New sequence: AGTTCCCACAAAATGGAGCTGTCTTGGCATGTAGTCTTT...[Sequence continues with another 80 bases] UAC encodes tyrosine, CAC encodes histine, per the coding table. (This question can be answered without use of the code table, but it is provided here as a resource.) What would the expected result of such a mutation be on the final protein product of the mutated gene (compared to the original, non-mutant product)? The protein will be very different from the original version, and likely non-functional. The protein will be cut short, ending after the first amino acid. There will be no protein produced at all. No change – the protein will be the same.…The following sequence is a double stranded DNA. 5'ATTTGACAATGCGTTAGGCATGACTATGTATAATGCATGCCACATACT... 3' 3'TAAACTGTTACGCAATCCGTACTGATACATATTACGTACGGTGTATGA…5' -35 -10 +1 Where does RNA polymerase initially binds?
- The coding DNA strand of a gene has the following DNA sequence: 5’ ATGGCGACGATAATGTTGTGTGAGTGA 3’ 1) Find the sequence of the mRNA that would be made from this gene. 2) Find the amino acid protein sequence that would be made from this gene 3) A mutation occurs at position 17 of the coding DNA strand, where the T is substituted with A (count from 5’ end of coding strand). Write the resulting mRNA and protein sequences. Show all your work!Which of the following set(s) of primers a–d couldyou use to amplify the following target DNA sequence, which is part of the last protein-coding exonof the CFTR gene?5′ GGCTAAGATCTGAATTTTCCGAG ... TTGGGCAATAATGTAGCGCCTT 3′3′ CCGATTCTAGACTTAAAAGGCTC ... AACCCGTTATTACATCGCGGAA 5′a. 5′ GGAAAATTCAGATCTTAG 3′;5′ TGGGCAATAATGTAGCGC 3′b. 5′ GCTAAGATCTGAATTTTC 3′;3′ ACCCGTTATTACATCGCG 5′c. 3′ GATTCTAGACTTAAAGGC 5′;3′ ACCCGTTATTACATCGCG 5′d. 5′ GCTAAGATCTGAATTTTC 3′;5′ TGGGCAATAATGTAGCGC 3′This is part of the Escherichia coli DNA sequence that contains an inverted repeat. (Note: top strand is the coding strand). 5'-AACGCATGAGAAAGCCCCCCGGAAGATCACCTTCCGGGGGCTTTATATAATTAGC-3' 3'-TTGCGTACTCTTTCGGGGGGCCTTCTAGTGGAAGGCCCCCGAAATATATTAATCG-5' Draw the structure of hairpin loop that will be formed during the end of transcription.
- The following represents a transcription unit in a hypothetical DNA molecule in E.coli. (Transcription can use either strand, but by convention we always put 5’à 3’ on the top.) 5’…..TTGACANNNNTATAAT…3’ 3’…..AACTGTNNNNATATTA…5’ If this molecule is transcribed from left to right, then the ____ strand will be the template strand and the ___ strand will be the non-template strand. top, bottom bottom, topBelow is the DNA sequence of a patient with overlapping genes (a single mRNA has multiple initiation points for translation) for two different proteins (DADαs and AMA): 5’- GTCCCAACCATGCCCACCGATCTTCCGCCTGCTTCTGAAGATGCGGGCCCAGGGAAATCTCTAACG-3’ 1. Indicate the DNA sequence coding for RNA. 2. Indicate the amino acid sequence of each of them.For this double stranded DNA: 3’-AGGTCCAGTCTTCGGCGGATGATCGGGCCAACCCCCGTAACTGGTCACCGGAATGCC-5’ 5’-TCCAGGTCAGAAGCCGCCTACTAGCCCGGTTGGGGGCATTGACCAGTGGCCTTACGG -3’ , while using the bottom strand is the template for transcription. If the START CODON is AUG and the STOP CODON IS UGA, how many amino acids are in the encoded protein and what is the primary structure?