T.L J =- (r* – r*) (Tubular shaft) Tr J = (Solid shaft) G.J 3. The shaft in the figure below consists of 75 mm diameter bronze segment that is rigidly joint to 50 diameter steel segment. The ends of the shaft are attached to rigid supports (fixed supports). Calculate the absolute maximum shear stress developed in each segment when the torque T= 5.1 kN-m is applied (a = 2 m and b = 1.5 m). Use G = 35 GPa for bronze, and G = 75 GPa for steel. (21 pts) 75 mm 50 mm Bronze Steel A T.

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter3: Torsion
Section: Chapter Questions
Problem 3.11.5P: A square tube section has side dimension of 20 in. arid thickness of 0.5 in. If the section is used...
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T.L
Tr4
%3D
J = " (r* – rf) (Tubular shaft)
Tr
(Solid shaft)
G.J
3. The shaft in the figure below consists of 75 mm diameter bronze segment that is rigidly joint to 50 diameter steel
segment. The ends of the shaft are attached to rigid supports (fixed supports). Calculate the absolute maximum shear
stress developed in each segment when the torque T= 5.1 kN-m is applied (a = 2 m and b = 1.5 m). Use G = 35 GPa for
bronze, and G = 75 GPa for steel. (21 pts)
75 mm
50 mm
Bronze
Steel
Transcribed Image Text:T.L Tr4 %3D J = " (r* – rf) (Tubular shaft) Tr (Solid shaft) G.J 3. The shaft in the figure below consists of 75 mm diameter bronze segment that is rigidly joint to 50 diameter steel segment. The ends of the shaft are attached to rigid supports (fixed supports). Calculate the absolute maximum shear stress developed in each segment when the torque T= 5.1 kN-m is applied (a = 2 m and b = 1.5 m). Use G = 35 GPa for bronze, and G = 75 GPa for steel. (21 pts) 75 mm 50 mm Bronze Steel
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