F3.A shaft is composed of two 6-in. diameter sections coupled together (see figure below). Part AB is bronze and part BC is steel. A torque is applied at the free end which causes a maximum shear stress in the bronze shaft of 10,000 psi. Find the angle of twist of the free end. Assume the modulus of rigidity of bronze is 6 (106) psi and that of steel is

1. A solid steel shaft ABCDE having diameter d = 40 mm turns with a constant angular velocity and freely in bearings at points A and E. The shaft is driven by a gear at C, which applies a torque T₂ = 625 N_m in the direction shown in the figure. Gears at B and D are driven by the shaft and have resisting torques T₁ and T3, acting in the opposite direction to the torque T2. We know T₁ = 400 N.m, but T3 is not explicitly given in the problem. Segments BC and CD have lengths LBC= 550 mm and LCD = 400 mm, respectively, and the shear modulus G = 80 GPa. Determine the maximum shear stress in each segment of the shaft and the angle of twist between gears B and D. pôrôć -LBC LCD T3 E

A steel stepped shaft ABCD fixed at A is subjected to three torques at points B, C and D, with magnitudes T₁ = 40 kip-in, T₂ = 50 kip-in and Ts= 30 kip-in and directions as shown in Figure 1.1. The segments AB and BC are solid with diameters dx = 3 in and dec = 2 in respectively, while segment CD is hollow with an outer diameter dan 1.5 in and a wall thickness of 0.25 in. The shear modulus of elasticity is equal to G=11.6x10³ ksl. T₁ T₂ 4 = 20 in A B L₂ = 20 in Figure 1.1 a) Draw the torsion moment diagram for the shaft and calculate how long should segment CD be so that the angle of twist between points B and D is equal to zero. T₁ 4₂-25 in b) If Ts is dropped, a fixed support is added at point D (as shown in Figure 1.2) and the length of segment CD is equal to 15 in, find the support reactions at points A and D and the maximum shear stress developed in segment BC. The magnitudes of the torques at points B and Care the same as in part a). B C L₂= 25 in T₂ * Figure 1.2 Hollow C Hollow…

Torsional T is applied to the hollow axis (G=80 GPa). Ewha Womans University, the maximum shear strain is γmax = 640 × 10-6rad Igo, inside andThe outside diameters are 120mm and 150mm, respectively.a. What is the maximum axial strain?b. Maximum axial stress?c. What is the maximum torque (T) meeting the above conditions?

A torsional bar is subjected to two external torques (10NM and 5Nm) and a distributed torque (15NM/m) at the locations indicated in the picture. The angle of twist at A (z = 0) is 0. The shcar modulus is 2GP.. Compute the following quantitics: (a) the reaction moment at A, (b) the angle of twist at B, and (c) the angle of twist at C. OD=5cm OD=4cm 15Nm/m 10Nm 5 Nm A 15 cm 10cm 8 cm 15 cm F A 8cm B C

Please help. This problem involves torsional stress and strain. Thank you.

A shaft ABCD is supported by a clamp at point A and is subjected to point torques at B, C and D, as shown in the figure. The shaft has variable cross-section and is solid in segments AB and CD and hollow in segment BC. The lengths and diameters of each segment are shown in the figure. Assume that the deformation is linear elastic and take the shear modulus of elasticity G = 12.1 × 10° psi. a) Using method of sections, plot the torsion moment diagram. b) Find the angle of twist for the free end (point D) with respect to the fixed support at A, QAD and the angle of twist for point C with respect to the fixed support at A, QCA. Find both angles in degrees. d₁ = 4 in d20 3.5 in, d2=2.5 in d3 = 3.0 in 25 kip-in 20 kip-in 10 kip-in A 20 in B с D ++ 25 in 30 in

The shaft in Figure below consists of a 3-in. -diameter aluminum segment that is rigidly joined to a 2-in. -diameter steel segment. The ends of the shaft are attached to rigid supports, Calculate the maximum shear stress developed in each segment when the torque T= 10 kip.in is applied. Use G = 4×106 psi for aluminum and G = 12×106 psi for steel. Aluminum 3-in. diameter 6 ft T Steel 2-in. diameter 3 ft