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It is given that
From tha table,
P-value = 0.055
And,
Significance level = 0.05
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- You are conducting a study to determine whether the educational level of voters is related to their attitudes towards a presidential candidate. You run the analysis in SPSS and receive the following output. Attitude Between Groups Within Groups Total Sum of Squares Answer: 4.844 39.067 43.911 What is the value of the test statistic? ANOVA df 2 42 44 Mean Square 2.422 .930 F 2.604 Sig. .086The mean BMI in patients free of diabetes was reported as 28.2. An investigator conduction the study hypothesizes that the BMI in patients free of diabetes is higher. Based on the data, is there evidence that the BMI is sigificantly higher than 28.2? Use a 5% level of significance. 25 . 27 . 31 . 33 . 26 . 28 . 41 . 24 . 32 . 35 . 40 .Your company wants to improve sales. Past sales data indicate that the average sale was €100 per transaction. After training your salesforce, recent sales data (taken from a sample of 25 salespeople) indicates an average sale of €130, with a standard deviation of €15. Did the training work to improve sales in the population? Test your hypothesis at a 5% alpha level. Is this a two-tailed test or a one-tailed test? Why? Answer: State the Null Hypothesis Answer: State the Alternative Hypothesis Answer: State the critical value(s) (make sure you are reading from the correct row-column combo on the T table) Answer: Calculate the t-test statistic or value (show your workings) Answer: Based on your answers to questions 18 & 19 are you rejecting or accepting the Null Hypothesis? Answer: What is the meaning of this in terms of the proplem posed? Answer:
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- You are conducting a study to see if the accuracy rate for fingerprint identification is significantly different from 0.51. Thus you are performing a two-tailed test. Your sample data produce the test statistic - 2.153. Find the p-value accurate to Z = - 4 decimal places. p-valueAccording to a survey conducted by the Association for Dressing and Sauces, 85% of American adults eat salad at least once a week. A nutritionist suspect that the percentage is higher that this. She conducts a survey of 200 American adults an finds that 171 of them eat salad at least once a week. Conduct the appropriate test that addresses the nutritionist's suspicions. Use the a = 0.1 level of significance. What is the test statistic? t-score population parameter Z-Score standard deviationThink about doing an Independent-Measures ANOVA, Step 3. If the data are as follows, find the SS-between. GROUP 1 GROUP 2 GROUP 3 1 3 5 3 2 7 2 4 6 Group of answer choices SS-between = 6.00 SS-between = 13.00 SS-between = 26.00 SS-between = 42.00
- A statistician changes her level of significance from .001 to .05. What impact will this change have on her risk of making a Type I and Type II error? Is the change in the level of significance a good decision? Why or why not?Use Excel to perform ANOVA on your data. After performing ANOVA, screenshot the table where the p-value is found. Are you going to accept or reject your hypothesis? Why or why not.