Using the table below, find the following for the Independent Measures ANOVA… use α= 0.05: dftotal= dfwithin= dfbetween= SStotal= SSwithin= SSbetween= MSbetween= MSwithin= F=  Fail to reject or reject the H0?   Biology                                           English                                                    Psychology                     N= 20 n1= 4                                          n2= 10                                             n3= 6                                      G= 250 M1= 9                                        M2= 13                                            M3= 14                                   k= 3 T1= 36                                       T2= 130                                            T3= 84                                    ƩX= 3377 SS1= 37                                     SS2= 90                                            SS3= 60

Find the first and third quartile for the data shown 4.5 4.9 7.2 9 9.9 11.2 13.3 17.6 17.9 25.6 Q1 = Q3 = %3D

options for first to blanks : 1- between 0.05 and 0.20 /2- greater than 0.20 / 3- less than 0.2  options for last blank : 1- handrubbing with alcohol / 2- handwashing with soap

Choose the appropriate statistical test. When computing, be sure to round each answer as indicated. A dentist wonders if depression affects ratings of tooth pain. In the general population, using a scale of 1-10 with higher values indicating more pain, the average pain rating for patients with toothaches is 6.8. A sample of 30 patients that show high levels of depression have an average pain rating of 7.1 (variance 0.8). What should the dentist determine? 1. Calculate the estimated standard error. (round to 3 decimals). [st.error] 2. What is thet-obtained? (round to 3 decimals). 3. What is the t-cv? (exact value) 4. What is your conclusion? Only type "Reject" or Retain"

A company that has a 10% market share (they sell their product to 10% of all potential buyers) launches a marketing campaign. At the end of the campaign period, the company conducts a survey in order to assess whether its market share has increased. The result of the survey issued to 500 customers was 12.5%.h0= p=0.10, h1= p>0.10test statistic= 1.86P value= 0.0314 a. State your conclusion using ΅ = 0.05.b. What would be the potential Type I and Type II errors in this problem? Explain these possible errors in context.

According to a survey conducted by the Association for Dressing and Sauces, 85% of American adults eat salad at least once a week. A nutritionist suspect that the percentage is higher that this. She conducts a survey of 200 American adults an finds that 171 of them eat salad at least once a week. Conduct the appropriate test that addresses the nutritionist's suspicions. Use the a = 0.1 level of significance. What is the test statistic? t-score population parameter Z-Score standard deviation

Vineyard Pines sells clothing online. In 2020, the mean value of orders placed with the company was $34.50. The President of the company made increasing the amount of the average order a priority for 2021. The company has just received the sales data for 2021. You just received the EXCEL file with details of the 400 orders in in the first quarter of 2021. You began by calculating the univariate statistics. Here are your findings:Total sales revenue:$14,000Number of orders in 2021:400Average order: $35.00Standard deviation of the individual orders: $5.20               Required: Determine the P-Value associated with the change in the average order total in 2021. Note that the company’s strategies for growth could have led to a reduction so we cannot assume a one-directional hypothesis. Given the number of data points (orders), you can assume a normal distribution and therefore assume a z-distribution for the data.

Think about doing an Independent-Measures ANOVA, Step 3.  If the data are as follows, find the SS-between.   GROUP 1 GROUP 2 GROUP 3 1 3 5 3 2 7 2 4 6   Group of answer choices SS-between = 6.00 SS-between = 13.00 SS-between = 26.00 SS-between = 42.00

Q7: what is the answer for both parts to this question, answer choices are provided in the pictures

A statistician changes her level of significance from .001 to .05.  What impact will this change have on her risk of making a Type I and Type II error?  Is the change in the level of significance a good decision?  Why or why not?