Q) Find the components of the forces G = 2 kN and K = 5 kN as shown in the * .following figure %3D G = 2 kN AY 20 F = 4 kN 40° 30° 40° H= 3 kN K = 5 kN

Answer for the 1st part of the problem.   magnitude of force A = 74 N direction of force A = 25o north of west second force = P direction of force P = α south of west arrow_forward The resultant of two forces is horizontal , it means that the y component of resultant = 0 Ry = ASin(25o) - PSin(α) 0 = (74×0.42) - PSin(α) PSin(α) = 31.08 NFor, the smallest force P , the value of Sinα must be maximum which is 1 when the value of αis 90 degree Thus, P×Sin(90o) = 31.08 N P = 31.08 N The magnitude of smallest force P = 31.08 N the direction of force P = 90 degree south of west = along - y axis= arrow pointing vertically downw

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We have 2 individuals pulling a marshmellow with ropes. The resultant force is directed along the positive x-axis. Person A is pulling at 60 degree angle. 1. Find what angle ? is if individual B is pulling twice as hard as individual A. 2. Draw the vector addition relationship between the force vectors ??, ??. Also, find FA and FB resultant force, shown using ?. Use either the parallelogram law or the triangle rule.

Tension at the cable is attached to B. With the given diagram find the Tension, supporting force reactions (Fax, Fay) at point A and the force acting in point C.

Consider the frame shown in (Figure 1). Suppose that F1 = 8 kN . Determine the x and y components of the force that the pin at B exerts on the frame using scalar notation. Determine the x and y components of the force that the pin at A exerts on the frame using scalar notation.

The two forces, F1 = 20 kN and F2 = 4 %3D kN are acting on a system shown in the figure. If 01 = 45° and 02 = 45°, what will be the values of Rx, Ry, R %3D %3D and the angle (0) makes by R with .the positive x-axis Y+ 02 F2 Y- Ry (1) R,= F; (2) R,= Fy; (3)R = (R + R;); (4)0 = tan1 Rx اخترأحد الخيارات a. Rx = 20.13 kN, Ry = 4.99 kN, R = 20.74 kN and 0 = 13.92° %3D b. Rx = 17.72 kN, Ry = 9.31 kN, R = 20.02 kN and 0 = 27.72° c. Rx = 20.95 kN, Ry = 5.62 kN, R = 21.70 kN and 0 = 15.02° %3D d. Rx = 16.97 kN, Ry = 11.31 kN, R = 20.39 kN ande = 33.68°

Assume that the 600 N force acts on the member EDC. How many members in the figure is or are they 3 forces? a. 1 b.0 c.2 d.3