Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
expand_more
expand_more
format_list_bulleted
Related questions
Concept explainers
Question
Transcribed Image Text:Add the following forces to find the resultant force.
V1 = 150 g @ 470
V2 = 550 @ 324°
V3 = 350 g @ 215°
V4 = 250 @ 172°
V5 = 450 g @ 285°
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution
Trending nowThis is a popular solution!
Step by stepSolved in 3 steps with 3 images
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- a) What are the tensions in each of the 4 cables supporting the lamp, if the lamp weighs 40 Ibs and the coordinate direction angles for Cable B are a = 95°, ß = 140° and y = 50.44°? Cable B Cable A 30 50 Cable C 3 ft Cable D b) Using the figure above, determine the maximum weight of the lamp if no cable can support more than 75 Ibs of tension? You can reuse the Cartesian force vector expressions for TA, TB And TC From part a. you do not need to derive them again for this part.arrow_forward8. Three forces act on the plate as 10 points shown in the figure below. Determine the sum of the moments of the three forces about point P. * 4 kN 45° 3 kN 30 0.18 m 0.10 m 20 0.12 m 12 kN 0.28 marrow_forwardThe forces acting on the arm of an athlete doing shoulder exercises are shown in the figure. The athlete holds his arm at an angle of β = 30° with the horizontal axis . Point O represents the axis of rotation in the shoulder joint, point A represents the connection point of the deltoid muscle to the humerus, point B represents the center of gravity of the arm, and point C represents the application point of the force acting on the hand. The distances between the rotation axis (O point) of the shoulder joint and the points A, B and C are a=22 cm , b =33 cm and c= 60 cm , respectively . A force of F= 120 N, which makes an angle of γ=30° with the vertical from the point C, acts on the athlete's hand . Weight of the athlete's armW= 80 N. The direction of application of the Fm muscle force makes an angle of α=20° with the longitudinal axis of the arm. According to this; a) Calculate the muscle strength F M b) Calculate the angle θ of the joint reaction force F J with the horizontal.…arrow_forward
- 6 in 60° 20 in Statics Instructor A vertical force of P = 100 lb is required to remove the nail at C from the board. Determine the magnitude of the moment about B exerted by the 100 lb vertical force. Draw a free body diagram for the system. Then, use what you know about moments to solve for Mp What is the magnitude of the moment at point B due to P if P = 100 lb and 9 = 10"? Round to the nearest whole number. Enter a response then click Submit below lb inarrow_forwardF1 F2 a C F3 d. F4 E B F5 Consider the following values: - a - 25 m; b - 5 m; c - 25 m; d - 5 m; F1 6 kN; F2 - 7 kN; F3 8 kN; F4 -9 kN; F5 - 10 kN; a = 30°, 0 = 60°, B= 45° 4] What is the resultant moment of the five forces acting on the rod about point D? a) - 177.8 kN.m b) 182.7 kN.m c) 121.9 kN.m d)- 228.6 kN.m e) -297.1 kN.m ) 230.1 kN.m Activate I 5] What is the moment of the force F2 about point E? c) 254.6 kN.m Go to Setting ) 321.3 kN.m a) 111.7 kN.m b) 218.1 kN.m d) 123.7 kN.m e) 101.1 kN.marrow_forwardThree cables are tightened to an eyebolt as shown in the figure. Determine the resultant force and its direction, exerted by the forces of the three cables.arrow_forward
- Solve it quickly pleasearrow_forwardF1 F2 F3 A b F4 D F5 Consider the following values: - a = 25 m; b 5 m; c = 25 m; d = 5 m; F1 = 4 kN; F2 = 5 kN; F3 = 6 kN; F4 = 7 kN; F5 = 8 kN; a = 30°, 0 = 60° %3D B = 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) - 75.8 kN.m b) 32.7 kN.m c) - 14.6 kN.m d) 72.9 kN.m e) 27.1 kN.m - 66.1 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) - 198.8 kN.m b) 212.7 kN.m c) - 121.6 kN.m d) 98.9 kN.m e) 125.4 kN.m f) -170.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) - 96.7 kN.m b) 251.1 kN.m c) - 114.6 kN.m d) 217.9 kN.m 154.1 kN.m f)-177.7 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) - 198 kN.m b) 127 kN.m c) – 219 kN.m d) 369 kN.m e) 151 kN.m f) - 171 kN.m Activate V 5] What is the moment of the force F2 about point E? Go to Settingarrow_forwardDetermine the magnitude and direction of the resultant for system of forces shown in the figure. Take F1 = 99.6 N, F2 = 43.7 N, F3 = 84.2 N, F4 = 66.0 N, F5 = 88.6 N, α = 29.8°, β = 50.2°, and γ = 55.1°. Sum of all horizontal force components, ΣH (N) = Sum of all Vertical force components, ΣV (N) = The resultant force, R (N) = The direction of the resultant force, θ (Degree) =arrow_forward
- i need the answer quicklyarrow_forwardUntitled Section F1 F2 a F3 d F4 Consider the following values: - F5 a = 16 m; b = 11 m; c = 13 m; d = 8 m; F1 = 3 kN; F2 = 11 kN; F3 = 2 kN; F4 = 20 kN; F5 = 2 kN; a = 30° , 0 = 60° , B = 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) 88.8 kN.m b) 76.3 kN.m c) 19.6 kN.m d) 55.5 kN.m e) 59.1 kN.m f) 81.3 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 88.8 kN.m b) 120.8 kN.m c) 31.6 kN.m d) 98.9 kN.m e) 41.1 kN.m f) 24.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) 125.7 kN.m b) 178.1 kN.m c) 254.6 kN.m d) 439.1 kN.m e) 144.1 kN.m f) 215.3 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) 77.8 kN.m b) 98.3 kN.m c) 100.6 kN.m d) 18.9 kN.m e) 97.1 kN.m f) 60.1 kN.m 5] What is the moment of the force F2 about point E? Activate V ) 151.3 kN.m Go to Setting! a) 122.7 kN.m b) 108.1 kN.m c) 66.6 kN.m d) 83.1 kN.m e)…arrow_forwardConsider the bracket shown in Fig-1. If: F1 = 10 N@ 120° • F2 = 75 N@ -90° then, what is the direction of the resultant force on the bracket? 176° 4.31° -4.31° 2.17° -176° -2.17° 94.3° -94.3°arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Elements Of ElectromagneticsMechanical EngineeringISBN:9780190698614Author:Sadiku, Matthew N. O.Publisher:Oxford University Press
Mechanics of Materials (10th Edition)Mechanical EngineeringISBN:9780134319650Author:Russell C. HibbelerPublisher:PEARSON
Thermodynamics: An Engineering ApproachMechanical EngineeringISBN:9781259822674Author:Yunus A. Cengel Dr., Michael A. BolesPublisher:McGraw-Hill Education 
Control Systems EngineeringMechanical EngineeringISBN:9781118170519Author:Norman S. NisePublisher:WILEY
Mechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage Learning
Engineering Mechanics: StaticsMechanical EngineeringISBN:9781118807330Author:James L. Meriam, L. G. Kraige, J. N. BoltonPublisher:WILEY
Elements Of Electromagnetics
Mechanical Engineering
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Oxford University Press
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:9780134319650
Author:Russell C. Hibbeler
Publisher:PEARSON
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:9781259822674
Author:Yunus A. Cengel Dr., Michael A. Boles
Publisher:McGraw-Hill Education
Control Systems Engineering
Mechanical Engineering
ISBN:9781118170519
Author:Norman S. Nise
Publisher:WILEY
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Cengage Learning
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:9781118807330
Author:James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:WILEY