Edge distances 75 mmdhole for tensile and rupture - d, +3 mmdhole for bearing strength for L- d, + 1.5 mmFy - 248 MPaFu 400 MPaFo 330 MPaUse LRFD design method.Determine the design strength due to the gross yielding of plates. (kN) Problem. A bolted connection shown consists of two plates 300 mm x 12 mmconnected by 4 - 22 mm diameter bolts.12 mm boltst=12 mmt=12 mmP.P-P 300757575Edge distances -75 mmdhole for tensile and rupture d, +3 mmdnole for bearing strength for L- de +1.5 mmFy 248 MPaF.- 400 MPa

solution: Using LRFD Design Method: φRn=φAbFn where; φ=Resistance factor = 0.75 Ab = Area of bolt…

Problem. A bolted connection shown consists of two plates 300 mm x 12 mm connected by 4- 22 mm diameter bolts. 12 mm bolts t12 mm t12 mm P, P- P. 300 75 75 75 Edge distances 75 mm dhole for tensile and rupture - de +3 mm dhole for bearing strength for Le d + 1.5 mm Fy 248 MPa F.-400 MPa

Problem. A bolted connection shown consists of two plates 300 mm x 12 mm connected by 4- 22 mm diameter bolts. 12 mm bolts t12 mm t12 mm P, P- P. 300 75 75 75 Edge distances 75 mm dhole for tensile and rupture - de +3 mm dhole for bearing strength for Le d + 1.5 mm Fy 248 MPa F.-400 MPa

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

Edge distances 75 mm
dhole for tensile and rupture - d, +3 mm
dhole for bearing strength for L- d, + 1.5 mm
Fy - 248 MPa
Fu 400 MPa
Fo 330 MPa
Use LRFD design method.
Determine the design strength due to the gross yielding of plates. (kN)

Problem. A bolted connection shown consists of two plates 300 mm x 12 mm
connected by 4 - 22 mm diameter bolts.
12 mm bolts
t=12 mm
t=12 mm
P.
P-
P 300
75
75
75
Edge distances -75 mm
dhole for tensile and rupture d, +3 mm
dnole for bearing strength for L- de +1.5 mm
Fy 248 MPa
F.- 400 MPa

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