A bolted connection shown is bolted with a A-325 bolts with an allowable shearing stress of 207 MPa. A-36 steel is used. The applied force "T" is equally divided among the bolts. Assume bolt hole diameter to be 3 mm bigger than bolt diameter. Diameter of bolt is 20 mm. T/2 T T/2 10 mr 10 mm T/2 300 mm T/2 Determine the capacity of the connection if shearing governs in kN.

A bolted connection shown is bolted with a A-325 bolts with an allowable shearing stress of 207 MPa. A-36 steel is used. The applied force "T" is equally divided among the bolts. Assume bolt hole diameter to be 3 mm bigger than bolt diameter. Diameter of bolt is 20 mm. T/2 T T/2 10 mr 10 mm T/2 300 mm T/2 Determine the capacity of the connection if shearing governs in kN.

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter3: Tension Members

Section: Chapter Questions

Problem 3.4.1P

See similar textbooks

Similar questions

STAGGERED CONNECTIONS: A PLATE WITH WIDTH OF 400 mm AND THICKNESS OF 12 mm IS TO BE CONNECTED TO A PLATE OF THE SAME WIDTH AND THICKNESS BY 34 mm DIAMETER BOLTS, AS SHOWN IN THE FIGURE. THE HOLES ARE 2 mm LARGER THAN THE BOLT DIAMETER. THE PLATE IS A36 STEEL WITH YIELD STRENGTH Fy = 248 MPa. ASSUME ALLOWABLE TENSILE STRESS ON NET AREA IS 0.60Fy. IT IS REQUIRED TO DETERMINE THE VALUE OF b SUCH THAT THE NET WIDTH ALONG BOLTS 1-2-3-4 IS EQUAL TO THE NET WIDTH ALONG BOLTS 1-2-4. a. CALCULATE THE VALUE OF b IN MILLIMETERS. b. CALCULATE THE VALUE OF THE NET AREA FOR TENSION IN PLATES IN SQUARE MILLIMETERS. c. CALCULATE THE VALUE OF P SO THAT THE ALLOWABLE TENSILE STRESS ON NET AREA WILL NOT BE EXCEEDED.
The connection shown is subjected to a tensile force of P = 100 kN. The allowable shear stress for the bolts is 100 MPa. Assume each bolt supports an equal portion of the load. Determine the required diameter of the bolts. a. 20.6 mm b. 25.2 mm c.35.7 mm d.17.8 mm choose letter of correct answer
Considering the following steel connection. The plates in Pink are 9mm steel plates. The middle plate (Yellow) is 18mm thick. The width of the plate is 100mm. The maximum allowable tension stresses on any of the plates is 100Mpa in Gross Area Yielding and 150 Mpa for Net Area or Tension Rupture. The bolts used are 8mm in diameter, the holes are 10mm in diameter, no need to add 1.6mm. The bolts allow a maximum of 280 Mpa of shear. Determine the maximum allowable "P" of the connection in kN.
Determine the design tensile strength of plate (200x8 mm) connected to 10-mm thick gusset using 20 mm bolts as shown in the figure, if the yield and the ultimate stress of the steel used are 250 MPa and 410 MPa, respectively. Add 1mm around the bolt for the hole. Use LRFD method. Plate 8-mm thick 2 3 40+ 30 301 T 200 mm Gusset 10-mm thick 3af 30 2_3 *40 40+ 50,54 +40
From the bolted connection shown, the diameter of bolts is 20 mm with the hole diameter equal to 3mm larger than the bolt diameter, the angular section is 100x75x8mm, with an area of 1340 mm^2. Thickness of gusset plate is 9 mm. the gusset plate. (a)If T = 200KN, compute the shearing stress on the bolts. (b)If the allowable shearing stress on the bolt is 145MPa, compute the value of T.
Problem. A bolted connection shown consists of two plates 300 mm x 12 mm connected by 4 - 22 mm diameter bolts. 12 mm bolts t=12 mm t=12 mm P. P- P 300 75 75 75 Edge distances -75 mm dhole for tensile and rupture d, +3 mm dnole for bearing strength for L- de +1.5 mm Fy 248 MPa F.- 400 MPa
A bolted connection shown consists of two plates 300mm x12mm connected by 4 - 22 mm diameter bolts. Edge distances = 75mm dhole for tensile and rupture = db + 3 mm dhole for bearing strength for Lc = db + 1.5 mm Fy = 248 Mpa Fu = 400 Mpa Fn = 330 Mpa Use LRFD design method. Determine the design strength due to the gross yielding of plates. (kN)
1. If the allowable stress of a revolving steel is 150 MPa, what is the equivalent angular velocity which will produce such stress. The mean diameter is 440mm. 2. See connection figure below. The rivets is 7/8 in. in diameter. According to the rivert supplier, the allowable stresses for the material are t = 15 ksi and Ob = 32 ksi. What is the allowable load of the connection? L4 x 3-1/2 W18 x 86 W24 x 117 Girder Beam
P4.002 Three bolts are used in the connection shown in the figure. The thickness of plate (1) is 15 mm. The ultimate shear strength of the bolts is 350 MPa, and the ultimate bearing strength of plate (1) is 375 MPa. Determine the minimum bolt diameter required to support an applied load of P = 155 kN if a minimum factor of safety of 2.8 is required with respect to both bolt shear and plate bearing failure. Answer: dbolt min = (1) mm
For the clevis connection shown, determine the shear stress in the 23-mm-diameter bolt for an applied load of P = 165 kN. O 141 MPa O 211 MPa O 167 MPa O 120 MPa O 199 MPa Clevis
The bolted connection shown must support an applied load of P = 2200 kN. The average shear stress in the bolts must be limited to 250 MPa. Determine the minimum bolt diameter that may be used in the connection. Answer: Minimum bolt diameter = i mm
Calculate and check the design strength of the connection shown below. Is the connection adequate for carrying the factored load of 65 kips. -3/8 in. А36 5 x % 125 АЗ6 2.50 65 k 1.25 % in, bolts 1.25 2.50 1.25