Apply AISC LRFD procedure to design a welded connection for a vertical truss member L127x76x9.5 with 10mm thick gusset plate using A36 steel and E60 electrode. The member is applied by a factored tensile force of 0.5R kN. Show your results on a sketch, complete with dimensions using standard notations. T=0.5R KN L 127 x76 x9.5 10 mm thick gusset plate Figure Q.3.
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Take R as 70
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- Six rivets are used in the connection shown in the figure. If both P=50KN, what is the minimum diameter rivet is necessary so as not exceed the 70MPa allow shearing stress? What thickness of plate is required so as not exceed a bearing stress of 140MPA? p= 50 80 mm 80 mm 100 mm* A 76 mm x 76mm x 6mm angular section is welded to a gusset plate having a thickness of 8mm as shown in the figure. The length L1 equals 125mm and L2 is 65mm. The angular section has a cross sectional area of 929mm2, Fy=248 MPa, Fu=400MPa. Determine the value of tensile force P based on block shear in gusset plate along the weld in kN. Allowable stresses: Allowable tensile stress (gross area) = 0.6Fy Allowable tensile stress (net area) = 0.50Fu Allowable shear stress (net area) = 0.30Fu P gusset plate L₂= 65 mm 25 mmTopic:Welded Connection - Civil Engineering -Steel Design *Use latest NSCP/NSCP 2015 formula to solve this problem *Please use hand written to solve this problem A tension member consists of a double angle section with long legs back to back. The angles are attached to a 9.5 mm thick gusset plate. Fu = 400 MPa Fy = 248 MPa for angular section. Fw = 480 MPa for 8 mm fillet weld. Reduction factor U = 0.80 Prop. of One Angle L 125m x 75m x 12.7 m A= 2419 mm2 y=44.45 mm Questions: a) Compute the design strength capacity of one angle. b) Compute the base metal shear strength (gusset plate) per unit length. c) Compute the length L1 and L2.
- A 100 x 100 x 10 mm angle is to be welded to a gusset plate. The angle carries a load of 200 kN applied along its centroidal axis which is 28.7 mm above the short leg as shown in the figure. Use an 8 mm fillet weld with a minimum tensile strength Fu = 483.33 MPa. Determine the length of a transverse fillet weld along the edge of the angle in order to avoid eccentricity of loading. Determine the length of side fillet weld required at the heel. Determine the length of side fillet weld required at the toe.STRENGTH OF MATERIAL(SIMPLE STRESS) PLEASE INCLUDE FBD 100% GUARANTEE UPVOTEDetermine the shear Load that act on the fillet weld that joining two plates together if the working stress is 11300 Ib/in? Throat
- Topic:Bolted Steel Connection - Civil Engineering -Steel Design *Use latest NSCP/NSCP 2015 formula to solve this problem *Please use hand written to solve this problem A 12.5 mm x150 mm plate is connected to a gusset plate having a thickness of 9.5 mm.Diameter of bolt = 20 mm Both the tension member and the gusset plate are of A 36 steel. Fy = 248 MPa, FU = 400 MPa. Shear stress of bolt Fnv = 300MPa. Questions: a.Determine the shear strength of the connection. b.Determine the bearing strength of the connection. c. Determine the block shear strength of the connection.An equal angle of area A has been welded on one side of gusset plate and carries tension along the axis. What is the effective area of the angle?The given plate below with width of 200 mm andthickness of 16 mm is to be connected to two plates ofthe same width with half the thickness by 20 mmdiameter rivets as shown. The rivet hole is 2 mm greaterthan the rivet diameter. Allowable tensile stress on netarea is 0.6Fy. Allowable bearing stress is 1.35Fy. plate: fy = 241 mpa fu = 4141 mpa rivet: fv = 152 mpa a. Determine maximum load P without exceeding allowable tensile stress on plate b. Determine maximum load P without exceeding allowable shear stress on rivets c. Determine maximum load P without exceeding allowable bearing stress between plates and rivets
- Topic:Welded Connection - Civil Engineering -Steel Design *Use latest NSCP/NSCP 2015 formula to solve this problem *Please use hand written to solve this problem A 150 mm x 90 mm x 12 mm angular section is welded to a gusset plate as shown. Area of the angle is 2736 sq.mm, allowable shear Fv is 150MPa, Allowable tensile stress Ft = 0.6Fy with Fy = 250 MPa. Questions: a) Design force P b) Total required length of weld using 12 mm fillet weld c) Value of “b”Determine the available tensilecapacity of the connection shownin the figure. The yield stress of theHSS 6.000 × 0.280 is Fy = 42 ksiand the tensile strength is Fu = 58ksi. The strength of the 1/2-ingusset plate and the 1/4-in filletweld is adequate.The relevant properties of theHSS 6.000 × 0.280 are obtainedfrom AISC Manual Table 1-13 asAg = 4.69 in²t = 0.260 inD = 6.0 inThe given plate below with width of 200 mm andthickness of 16 mm is to be connected to two plates ofthe same width with half the thickness by 20 mmdiameter rivets as shown. The rivet hole is 2 mm greaterthan the rivet diameter. Allowable tensile stress on netarea is 0.6Fy. Allowable bearing stress is 1.35Fy. Use a501 plate and a502 gr2 rivet a. Determine maximum load P without exceeding allowable tensile stress on plate b. Determine maximum load P without exceeding allowable shear stress on rivets c. Determine maximum load P without exceeding allowable bearing stress between plates and rivets