o normal temperatures but wet in-service conditions. Assume =0.95 and the geometry factor is CA=1. The controlling ASD nere L is from occupancy. Cross Section L4x4x1/4 L4x4x1/4 Pa 2L4x4x1/4 4x10 4x10 DI

Steel Design (Activate Learning with these NEW titles from Engineering!)
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Author:Segui, William T.
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Chapter8: Eccentric Connections
Section: Chapter Questions
Problem 8.6.4P
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A tension connection consists of A36 steel double angles (two L4x4x1/4 shapes, or 2L4x4x1/4)
fastened to a 4x10 No. 2 Red Oak member with a single row of four 0.875 inch A307 bolts.
The connection is subjected to normal temperatures but wet in-service conditions. Assume
the group action factor is C,=0.95 and the geometry factor is Ca=1. The controlling ASD
load combination is D+ L where L is from occupancy.
Elevation
Cross Section
L4x4x1/4
L4x4x1/4
Pa
Р.
2L4x4x1/4
4х10
4x10
Plan
L4x4x1/4
Pa/2
Pa
4x10
L4x4x1/4
Pa/2
• Determine the load, Pa, that the connection can support based on tension strength of
the 4x10.
Pa=.
lb
• Determine the load, Pa, that the connection can support based on gross tension yield
of the double angles. The ASD design strength for gross tension yield is F,A,/1.67
where F=36 ksi, A,=1.93 in² for each L4x4x1/4.
Pa=.
lb
Transcribed Image Text:A tension connection consists of A36 steel double angles (two L4x4x1/4 shapes, or 2L4x4x1/4) fastened to a 4x10 No. 2 Red Oak member with a single row of four 0.875 inch A307 bolts. The connection is subjected to normal temperatures but wet in-service conditions. Assume the group action factor is C,=0.95 and the geometry factor is Ca=1. The controlling ASD load combination is D+ L where L is from occupancy. Elevation Cross Section L4x4x1/4 L4x4x1/4 Pa Р. 2L4x4x1/4 4х10 4x10 Plan L4x4x1/4 Pa/2 Pa 4x10 L4x4x1/4 Pa/2 • Determine the load, Pa, that the connection can support based on tension strength of the 4x10. Pa=. lb • Determine the load, Pa, that the connection can support based on gross tension yield of the double angles. The ASD design strength for gross tension yield is F,A,/1.67 where F=36 ksi, A,=1.93 in² for each L4x4x1/4. Pa=. lb
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