Problem 1: For the circuit shown in the figure, find the following: a) The current (I1) b) The current (14) c) The current (12) E₁ 12 V d) The voltage drop (V2) e) The voltage difference (Vab) R₁=42 w ㄧㄠˇ R2=2Ω< R₁=402 w h R₁=502 ww E₂ 4 2 V + Vab
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- the adjoining figure. This lamp can withstand a maximum voltage 3.0 v 0.4 9. Volt-ampere (V-I) charaeteristics of an incandescent lamp 16thd in and a maximum current 0.4 A. An infinite ladder network consisting a large number of these lamps is also shown in the figure given belo How much maximum voltage can be applied between the terminals A and B, so that no lamp gets damaged? (Use V5 = 2.2). Ans:x4.2V Hint: Curentin all bulls except first isA dc generator and a battery are connected to a resistive load RL in the figure below. For each, determine the value of RL for maximum power transfer to RL. Next is to determine RL to 75% efficiency8 The figure is a graph of . Current Voltage the current across a voltage as a function of the potential difference through it the resistance as a function of the current across a component the current through a component as a function of the voltage across it O All three of the above (a), (b), and (c) are true O None of the above (a), (b), or (c) is trueWhat is the difference between the cut-off voltage VGS0 f and the narrowing voltage Vp? Explain this with the diagramWhich of the following statements are correct for the circuit below? Thanks to the capacitors I – C1 and C2, the voltage gain of the circuit increases. II – Capacitors C1 and C2 are coupling capacitors and provide an isolation function between AC and DC voltages in the circuit. Thanks to the III – RE resistor, the voltage gain of the circuit increases. Thanks to the IV – RE resistor, the stability of the circuit increases. The V – C3 Capacitor is a bypass capacitor and prevents the loss of voltage gain. Capacitor VI – C3 is a coupling capacitor and has no effect on the voltage gain in the circuit. VII – As the value of the source internal resistance Rs increases, the voltage gain decreases. VIII – The voltage gain decreases as the value of any RL load to be added to the circuit increasesThe diagram in the figure shows a simple circuit consisting of a battery and a load consisting of two resistors.The battery voltage is UB = 56 V and the value of the resistors is:R1 = 1800R2 = 5400a) The ammeters in the circuit show the following value:A1 shows valueA2 shows valueA3 shows valueb) In the load, the effect developsc) The total resistance of the load is2 The figure is a graph of ... 5 (5 Points) Current Voltage the current across a voltage as a function of the potential difference through it the resistance as a function of the current across a component the current through a component as a function of the voltage across it All three of the above (a), (b), and (c) are true None of the above (a), (b), or (c) is trueplease sketch them all and show a step by step solutionDetermine E and P3. Given R1 = 10ohms, R2 = 20ohms, R3 = 60 ohms, R4= 10ohms, R5= 20ohms, R6= 60ohms, R7= 10 ohms, R8= 20 ohms. R9= 30ohms, P6 = 540W.Consider the series-parallel circuit shown in the figure below with various multimeters connected in the circuit. Assum that XMM1 has been configured in ammeter mode, and XMM2 has been configured in voltmeter mode. XMM1 R1 1kQ XMM2 R2 R3 V1 1kQ 1kQ 12V 3.1: Redraw the circuit replacing XMM1 and XMM2 by their equivalent circuit models 3.2: Assume that XMM2 was incorrectly configured in ammeter mode. Redraw the equivalent circuit from 3.1 and compute the current that would be measured by the ammeter in this scenario. Hil-c). write the current equation for the circuit below 60 mA 20 mA 14 Is 40 mA 30 mA Determine the missing currents from the equation in c).A five-Ohm resistor is in series with a 0.001-Henry inductor and is supplied from a 10-V DC source. Solve for the current 2 milliseconds after the switch was turned on. a. 2.0000 Amperes b.1.9999 Amperes c.1.0001 Amperes d. 2.0001 AmperesSEE MORE QUESTIONS