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Sample |
Relative Concentration of Tea Extracts |
% Inhibition |
Green Tea ( 0.25 mg ) |
0.25 |
0.974 |
Green Tea ( 0.5 mg ) |
0.5 |
0.967 |
Green Tea ( 0.75 mg ) |
0.75 |
0.965 |
Green Tea ( 1.5 mg ) |
1.5 |
0.959 |
Back tea ( 0.25 mg ) |
0.25 |
0.858 |
Black tea ( 0.5 mg ) |
0.5 |
0.976 |
Back tea ( 0.75 mg ) |
0.75 |
0.982 |
Black tea ( 1.5 mg ) |
1.5 |
0.969 |
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- Relative Concentration of Tea Extracts % Inhibition 0.25 0.974 0.5 0.967 0.75 0.965 1.5 0.959 0.25 0.858 0.5 0.976 0.75 0.982 1.5 0.969 0.25 0.974 plot the graphThe table below shows the results. Concentration of sugar solution in mol/dm³ 0.0 0.1 0.2 0.3 0.4 0.5 Mass of potato at start in grams 7.94 7.95 7.96 7.93 7.93 7.95 Mass of potato after 24 hours in grams 10.14 Page 1 of 5 9.10 8.21 7.53 7.18 7.00 Change in mass in grams 2.20 1.15 0.25 -0.40 -0.75 -0.95 Explain why the potato in 0.0 mol/dm³ sugar solution increased in mass.Rx Clindamycin phosphate 4% w/v Propylene glycol 12.9% w/v Purified water 11% w/v Isopropyl alcohol ad 244 mL (Sp.G. = 0.880) Ft. clindamycin gel Sig.: Place thin layer onto affected areas How many grams of isopropyl alcohol are present in a clindamycin gel that has 76 mL of purified water? Assume negligible volume shrinkage as result of mixing these ingredients. Answer: 415.2 (please show all work) ANSWER IS ALREADY GIVEN PLEASE SHOW WORK IN DETAIL HOW IT COMES
- Table 1 - Comparison of the effect of catechol concentration on the amount of product formed. Absorbance Potato extract Absorbance 0 mins after 30mins (2nd reading) (mL) 1st reading 1 Tube # la blank 2a 3a 4a 1 1 1 dH₂O Catechol (mL) (mL) 7 5 3 1 0 2 4 6 0.00 0.060 0.033 0-05-2 Q4) Give 2 reasons for adding dH₂O to these tubes in Table 1? Time for reading: 3:21 -0.11 Absorbance: Time for reading: 3.36 Q5) Tube la serves as a control, but why is this control needed? Absorbance: 0.197 Time for reading: 3.37 Based on the data from Table 1 answer these questions: Q1) What is the name of the enzyme found in potato extract? Answer: catechol Q2) What is the substrate? Answer: THO Q3) Name of product of this enzyme catalyzed reaction? Answer: Absorbance: 0.152 Time for reading: 3:39 Absorbance: . 166 ness Catechol Benzoquinone Subtract 1st from 2nd reading -0.01 0-137 0.11.19 0.119 Q6) Notice that your 1st absorbance reading in tubes 2a-4a are quite similar but it then becomes very different…Prepare one dose of 0.6 mg kanamycin in 2mL diluted from a stock solution of 20 mg/ml. How much kanamycin and how much diluent are used?Solution Absorbance mg/ml aspirin Standard solution - 1.6 mg/mL A 0.638 0.08 mg/mL B 0.504 0.064 mg/mL C 0.376 0.048 mg/mL D 0.259 0.032 mg/mL E 0.126 0.016 mg/mL A = -log T where T = %T ÷ 100 Construct a callibration curve using the above data. Absorbance should be on the vertical axis and "mg/mL of acetylsalicylic acid" on the horizontal axis. The line should go through the origin. Using the data provided, the graph you have generated, and the procedure that was used to generate the solutions which were examined by spectroscopy, calculate the amount of acetylsalicylic acid per tablet. Commercial tablet 1 labelled as 100 mg enteric coated Absorbance = 0.16 Commercial tablet 2 labelled as 300 mg Absorbance = 0.45 Student prepared tablet from practical 5 Absorbance = 0.19 Using the data provided, the graph you have generated, and the procedure that was used…
- Codeine 6 mg/ mL Simple syrup qs ad 2 floz (60 mL) a. Calculate the number of grams of codeine needed b. If we have codeine 30 mg tablets in stock, how many tablets are required? c. Calculate the percentage strength and ratio strength of this preparation 2. Acetazolamide Using Acetazolamide 250 mg tabs X 10 Simple syrup qs 100 mL a. Make qs 250 mL b. Find concentration34. A dermatologic lotion contains 1.25 mL of liquefied phenol in 500 mL. Calculate the percentage (v/v) of liquefied phenol in the lotion. 34. 0.25% v/v liquefied phenolDate Sheet Extraction ODD EVEN ODD EVEN GROUP Single Extraction 1 Single Extraction 2 Multiple Extraction 1 Multiple Extraction 2 Weight of tea leaves 10.002 (g) 10.123 (g) 10.013 (g) 10.007 (g) Weight of evaporating dish + caffeine 123.689 (g) 124.334 (g) 121.815 (g) 126.523 (g) Weight of empty evaporating dish 123.513 (g) 124.147 (g) 121.614 (g) 126.246 (g) Weight of caffeine Post Lab Questions Explain the principles involved in extraction. What other organic compounds can be extracted from tea bags? Draw their structures and briefly mention their biological function/s. Why do you need to add sodium carbonate in the extraction process?
- Date Sheet Extraction ODD EVEN ODD EVEN GROUP Single Extraction 1 Single Extraction 2 Multiple Extraction 1 Multiple Extraction 2 Weight of tea leaves 10.002 (g) 10.123 (g) 10.013 (g) 10.007 (g) Weight of evaporating dish + caffeine 123.689 (g) 124.334 (g) 121.815 (g) 126.523 (g) Weight of empty evaporating dish 123.513 (g) 124.147 (g) 121.614 (g) 126.246 (g) Weight of caffeine 1. Identify the two layers in the procedure. In which part does caffeine can be extracted? 2. The partition coefficient K for a compound between dichloromethane and water is determined to be 56 : 1 (K=56). If 10.0 mg of the compound is dissolved in 50.0 mL of water and this solution extracted with 25.0 mL of dichloromethane, how many mg of the compound will remain in the water layer following the extraction procedure? Show you calculations1000 Tablets 48, Kandivli Ind Estate, Mumbai 400 067, India by: Ipca Laboratories Limited Jacksonville, FL 32257 USA Ranbaxy Pharmaceuticals Inc. Manufactured for Rx only LOT: EXP: 100 mg TABLETS, USP ALLOPURINOL N Each scored tablet contains: Allopurinol, USP........100 mg Store at 20° to 25°C (68° to 77° F) [See USP Controlled Room Temperature]. Dispense in tight, light-resistant container as defined in the USP. USUAL DOSE: One tablet daily. For indications, dosage, precautions, etc., see accompanying package insert. Code: DNH/DRUGS/NH/170 3 633041153910 NDC 63304-539-10 Non varnish area R RANBAXY LBZTL6 0311 Expiration date Prescription warning Total amount in vial, packet, box Usual adult dose Dosage strength Drug form Lot number (control number) National Drug Code (N D C) # Manufacturer Brand name Generic nameHow much caffeine can be extracted using 50.0ml of DCM if a tea bag contains 15 grams of tea leaves with 0.9% of caffeine? And has undergone solid-liquid extraction with 100ml of distilled water followed by liquid-liquid extraction using DCM. The solubility of caffeine requires 15 ml of water and 2.0ml of DCM for 40.0mg.