PR PR Reliable Glucose Base Interpretation Y/N? A/G A/G A/G -/- A/G K A/G A/– K K K -/- A/– K A/– A/G

Please help me to find positive or negative results for the Oxidase lab test for microbiology, recognize the species and explain the reason behind the result.

Gelatin Hydrolase: 1. Explain the incubation conditions 2. Explain the reagents being added 3. Explain the observations in Gelatin Hydrolase 4. Explain the interpretations in Gelatin Hydrolase

In an electrochemical cell, Q = 0.00025 and K = 0.70. What can you conclude about Ecell and E°cell?     Ecell is positive and E°cell is positive     Ecell is negative and E°cell is positive     Ecell is negative and E°cell is negative     Ecell is positive and E°cell is negative

QUESTION 3: What is the purpose of the Tris-Acetate-EDTA (TAE) buffer that will be used to prepare and run the agarose gel? What would happen if you used water to prepare and run the gel instead of TAE buffer? (You should conduct an internet search to answer this question but answers should be in your own words. Please include a reference for any sources you used)

in the SIM test, the S part checks for: fermentation of sugar fermentation of sulfur synthesis of ferric citrate reduction of sulfur reduction of sugar

Catalase Yeast Test Questions: 1. Why is it important to graph volumes that did not include the initial volume? 2.  How might the temperature of the yeast mixture affect a reaction? 3. What effect would increasing the amount of yeast have on a reaction?

Aspergillus can be used to produce α-amylase (α-AM), which is an enzyme that hydrolyzes the glycosidic bonds in starch molecules into maltose (disaccharide). Pure α-AM has a specific activity of 56.00 U/mg. The α-AM is secreted into the culture media during production (after 5 days, production is complete). Following, the Aspergilluscells are separated by centrifugation and discarded. The culture supernatant (with α-AM) is filtered giving a clarified supernatant with a volume of 100.0 L, activity of 3.00 U/mL, and total protein concentration of 0.650 mg/mL. After purification, the product stream (7.50 L) contains α-AM (25.00 U/mL) and a total of 6.788 x 103 mg total protein. Calculate the following: Concentration of total protein (g/L) and total units of activity in the clarified supernatant and purification product stream. Specific activities (U/g) of the clarified supernatant and purification product stream. Consider significant figures in your answers (may want to use scientific…