Star-connected 3+ supply Phase 3 (grey) Filtered Current Voltage sensors 1V/A Ө 13 V3 10 Phase 2 (black) Black Phase 1 (brown) Red Line currents 11 Power Neutral current 0.00 се Three-phase star-connected power supply (24V line) V2 CH2 brown V1 Star-connected balanced loads with neutral connection HEA› HFA³· HEA Im . m 1. m www 10 Ω 30 mH 100 μF 200 µF 400 μF +10 adaptors both channels Line 3 A Line 2 A Line 1 A Neutral ww www Figure 7 00000 · Delta- connected balanced load 102+ 200 µF 10 Ω (Delta) Black V12 V Red V2N Brown Brown VIN CH1 (N) CH2N Blue Blue Figure 8 L3 Induction Motor L2 L1 + Phase voltage Line and phase voltage measurements Phase voltage V1N, potential difference of line 1 with respect to 13.2V (phase 1) neutral (rms) Phase voltage Phase voltage V2N, potential -6.8ms (phase 2) difference of line 2 with respect to neutral (rms) Line voltage Line-to-line (line) voltage 23.8V (phases 1-2) (rms), V12 from meter Time difference for V12 *Phase angle for V12 rel to V1N 1.8ms 32.8deg *Calculate later to allow you to complete phasor diagram Draw accurately and to scale the phasor diagram showing how the rms magnitudes and phases of the line voltages V12, V23 and V31 relate to the phase voltages V1N, V2N and V3N, and use your diagram to show specifically (using your measured magnitude and phase of V12) that V12 = V1N- V2N

In the above figure, a single line model of a three-phase power system is given. Base power 50MVA, base voltage 13.8kV according to its value, a) Per-unit values ​​of power system circuit elements according to the given base power and base voltage values. calculate. b) The perunit you calculate by drawing the equivalent impedance circuit for one phase of the power system given in the figure. show on the values.

Consider the single-Line diagram of a power system shown in Figure 3.42 with equipment ratings given: Generator G1: 50MVA,13.2kV,x=0.15p.u. Generator G2: 20MVA,13.8kV,x=0.15p.u. Three-phase -Y transformer T1: 80MVA,13.2/165YkV,X=0.1p.u. Three-phase Y- transformer T2: 40MVA,165Y/13.8kV,X=0.1p.u. Load: 40MVA,0.8PFlagging,operatingat150kV Choose a base of 100 MVA for the system and 132-kV base in the transmission-line circuit. Let the load be modeled as a parallel combination of resistance and inductance. Neglect transformer phase shifts. Draw a per-phase equivalent circuit of the system showing all impedances in per unit.

Id is :  510221

High voltage engineering subject

Q20. The section bus-bars A and B as shown in Figure B5 are linked by a bus-bar reactors each rated at 5000 kVA with 10% reactance. On bus-bar A, there are two generators each of 10,000 kVA with 10% reactance and on B two generators each of 8000 kVA with 12 % reactance. Find the Current and MVA that fed into a dead short circuit between all phases on B with bus-bar reactor in the circuit. Page 4 of 5 جامعة التقنية والعلومر التطبيقية بإبراء University of Technology and Applied Sciences - Ibra Student ID: Section: Student Name: 8,000 kVA 12% 10,000 kVA 10,000 kVA 10% 8,000 kVA 12% 10% 2 3 5,000 kVA 10% lell 8,000 kVA 10% Figure B5 "End of Question Paper"

For transferring electrical power at 220 kV, six conductors of ACSR Drake constitute a 60Hz double circuit three phase line arranged as shown below. The vertical spacing between consecutive conductors is 14ft; the longer horizontal distance is 32ft whereas the shorter horizontal distance is 25ft. a. Find the inductance per phase per mile and the inductive reactance per phase in ohms per mile. b. Find the capacitive reactance to neutral in ohm-miles. c. Find the resistance per phase per mile in ohms per miles. d. If the length of the line is 90 miles then draw an equivalent circuit of the line and analyse the open circuit and short circuit performance of the line. e. Find the maximum power we can transmit over the line. f. If the line is delivering power to a load of 20MW at 0.8 power factor lagging then find the voltage at the receiving end of the line. Also, Determine the voltage regulation, losses and efficiency of the line. g. If a fixed shunt compensation of 3 MVAr is attached at…

Q2. The single-line diagram of a simple three-bus power system is shown in Figure-2. Each generator is represented by an emf behind the sub-transient reactance. All impedances are expressed in per unit on a common MVA base. All resistances and shunt capacitances are neglected. The generators are operating on no load at their rated voltage with their emfs in phase. A three-phase fault occurs at bus 3 through a fault impedance of Zf = j0.19 per unit. (i) Using Th'evenin's theorem, obtain the impedance to the point of fault and the fault current in (ii) Determine the bus voltages per unit. ) j0.05 j0.075 j0.75 2 j0.30 j0.45 Figure-2: Single line diagram of the power system network for Q2 3

A short transmission line connects a step-up transformer on the source side with a series impedance of j0.5 ohms (referred to the primary) to a step-down transformer on the load side with a series impedance of 50 ohms (referred to the primary). The turn ratio of the step-up transformer is 1:10 and a no-load primary voltage of 23 (line-to-line) kV. The step-down transformer has a turn ratio of 35:2 and it has a Y-connected, balanced load of 0.490 +j 0.0816 ohms connected to its secondary side. Assuming an ideal transmission line, compute the load voltage (line-to-neutral).

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