LIFE SCIENCES/GRADE 10 ESTION 3 FET Read the extract below and answer the questions that follow. MDE/AUGUST 2024 Carolus Linnaeus established a hierarchical classification system of grouping similar organisms together. He grouped organisms from broad groups called Kingdoms down to the smallest groups called species. By making use of his system, a lion is fully classified as follows: Animalia, Chordata, Mammalia, Carnivore, Felidae, panthera leo 3.1.1 According to Linnaeus' system, which class does the lion belong to? (1) 3.1.2 The lion's scientific or binomial name, panthera leo, has been written incorrect Rewrite it correctly. 3.1.3 Why is it necessary for organisms to have scientific names? 25 (2) (5) 2 The table below shows the results of an investigation which measured the average global carbon dioxide levels in the atmosphere over a five-year period. Year Carbon dioxide level (parts per million) 2004 376,0 2005 377,0 2006 379,5 2007 381,0 2008 383,5 3.2.1 Draw a line graph to show the change in carbon dioxide levels over time. 3.2.2 Identify the dependent variable in this investigation? 3.2.3 Calculate the increase in carbon dioxide levels from 2004 to 2008. Show ALL calculations. 3.2.4 Name TWO human activities that cause an increase in the carbon footprint in the atmosphere. TOTAL SECTION B: GRAND TOTAL: (6 (1 (2

student found a bottle of unknown origin in the basement of an "CAUTION—contains С₁H₁O.” No other A old house. The bottle was labelled information was given, but inside the bottle were some white crystals. The student took the bottle to a chemistry laboratory, where she analyzed the crystals with the help of the laboratory staff. C₁2H₁6O reacted with Br₂ in CCl4 adding one mole of Br, and forming C₁₂H₁OB2₂. When a sample of C₁₂H₂O was reacted with O3 followed by Zn/H₂O, two different samples, J and K, were obtained. Compound J had a molecular formula of C.HgO₂, and its NMR is shown below. Compound K had a molecular formula of C₂H₂O, and it could be oxidized to compound L, with a molecular formula of C₂H₂O₂. The IR spectrum of L showed a very wide, strong band centred around 3000 cm*¹. The NMR spectrum of L showed only two different absorptions: a doublet (6H) at 0.9 ppm and a septet (1H) at 3.6 ppm. There was also a singlet (1H) off the scale at 11.8 ppm. students, deduce possible…

C Indicate in wh. x Ciam seeing n 01058112023#/ d e S 56 myhp Part A Palmitate, urate, arachidate: Submit × 9 New Tab How long is a single molecule of palmitate (16 carbon atoms) in its fully extended form? What about molecules of laurate (12C) and arachidate (20C)? Express your answers to one decimal place separated by commas. Request Answer Part B Complete previous part(s) Part C Complete previous part(s) C- Part D Complete previous part(s) X + Start Dictation [^] VO ΑΣΦ

2. C12H24(I) + O2(g)