SOLVE STEP BY STEP IN DIGITAL FORMAT Structure of Metal Materials: 8. A colleague calculated the density of iron with BCC structure using the following data of atomic radius equal to 1.24 Angstrom and atomic weight of 55.85 as follows: p = [(4 atoms/C. U.) x (55.85 g/atomic weight) / (atoms/atomic weight) / [2(1.24x108 cm)/√2]³ p = 68.8 g/cm³

SOLVE STEP BY STEP IN DIGITAL FORMAT Structure of Metal Materials: 8. A colleague calculated the density of iron with BCC structure using the following data of atomic radius equal to 1.24 Angstrom and atomic weight of 55.85 as follows: p = [(4 atoms/C. U.) x (55.85 g/atomic weight) / (atoms/atomic weight) / [2(1.24x108 cm)/√2]³ p = 68.8 g/cm³

Chemistry for Engineering Students

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ISBN:9781337398909

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter2: Atoms And Molecules

Section: Chapter Questions

Problem 2.95PAE: 2.95 Engineers who design bicycle frames are familiar with the densities of aluminium (2.699 g/cm3),...

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デジタル形式で段階的に解決ありがとう!!
SOLVE STEP BY STEP IN DIGITAL FORMAT
Structure of Metal Materials:
8. A colleague calculated the density of iron with BCC
structure using the following data of atomic radius equal to
1.24 Angstrom and atomic weight of 55.85 as follows:
p = [(4 atoms / C. U.) x (55.85 g/atomic weight)/(atoms/atomic weight) / [2(1.24x108 cm)/√2]³
p = 68.8 g/cm³
Is the result obtained logical? Explain and justify your
answer.

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