Java [1] Performing a check of constraints on node values for each sub-tree, just the way we discussed in the Lecture this week. Please remember what we dis[1]cussed in the Lecture - that - for a Binary Tree to qualify as a Binary Search Tree, we must perform the node values check of-course but also must not forget the value checks at the sub-tree level.   [2] Performing the BST check by doing an In-Order Traversal of the Binary Tree as discussed in the Lecture. Since we know that an in-order traversal of a BST results in nodes being processed in sorted order, as soon as there is a violation of sorted order, we would know that the tree provided is not a BST.

Design an algorithm and write code to find the first common ancestorof two nodes in a binary tree. Avoid storing additional nodes in a data structure. NOTE: This is not unecessarily a binary search tree.

Q#A hierarchical tree structure has a self-similar structure. What does this mean? Group of answer choices 1. Each branch of the tree must be balanced, so all sub-trees have the same number of internal and leaf nodes.   2. Two different hierarchies will have the same structures.   3. It means that any operations that add or delete elements, they must first create a duplicate structure, and remove or add elements from that similar structure.   4. Each sub-part of the hierarchy is also a hierarchy.

Hello there, I have to write a Binary Search Tree program in Java that has to insert, delete, search, find max, find min, printing the elements in Binary Search Tree in pre-order, post-order, and in-order. But I am struggling to understand how I can print the pre-order, post-order, and in-order elements with its frequency. Can someone help me with the question I have, please?  Question: Printing an element: An element from the BST will always be printed along with its frequency. For example, if there is a node in the BST that contains the element −7, and its frequency is presently recorded as 2, the data in the node will be printed as−7(2)   Another example:    1 100 1 50 1 50 1 100 1 100 5 6 0  Output: 100(3)50(2)50(2)100(3)   Hope someone can help me understand the coding, please :)   Thank you.