Design an algorithm and write code to find the first common ancestor of two nodes in a binary tree. Avoid storing additional nodes in a data structure. NOTE: This is not unecessarily a binary search tree.

C++ 2 Binary search tree Consider the following BSTNode structure that represents a binary search tree node, and the BSTree structure that represents a binary search tree. The root pointer points to the root node, and size book-keeps the number of items in the binary search tree. template struct BSTNode ( T data; BSTNode left; BSTNode right; // BSTNode. parent; BSTNode (T d) : data (d), left (0), right (0)/, parent (0) / 0 // invariant 1: // (left // invariant 21 (right! null) inplies (data struct BSTree ( BSTNode root; unsigned int size: BSTree () BSTNode BSTNode BSTNode .min(); root (NULL), size (0) () insert (T d); find (T d); BSTNode next (BSTNode current); void renove (BSTNode node); //invariant: // (root = null) equiv (size -- 0) }; Implement the insert and find methods. insert should insert element d in the tree, and find takes an element d and returns a pointer to the node that has d as value if it exists. Otherwise, it returns NULL. • Implement the min, and next…

Given the following keys T, Y, V, Q, F, B, M. N, W, G, C, A, P, R, L. 1. Assuming the keys are inputted in that order, build a binary search tree according to the input: 2. Use an array to implement the tree you built and show the contents of the array: 3. Assuming the keys are all available at once and you can change the order if necessary, build a balanced binary search tree:

To determine the earliest common ancestor of two nodes in a binary tree, devise a method and build the necessary code. Do not add more nodes to a data structure. NOTE: A binary search tree is not required in this case.