In humans, sickle cell anemia is an autosomal recessive disorder. There are two alleles at this locus, the normal allele, "A" and the recessive allele, "a", which is associated with sickle cell anemia. A recent study of 3,560 people showed that 2,357 were homozygous dominant at this locus; 1,052 were carriers of the disorder and 151 were affected. What is the expected frequency of the homozygous dominant individuals, if the population is in Hardy.Weinberg equilibrium? (Round your answer to the nearest hundredth, for example: 0.167 0.17, but use the unrounded number to continue with the chi square question).
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- Given the karyotype shown at right, is this a male or a female? Normal or abnormal? What would the phenotype of this individual be?As it turned out, one of the tallest Potsdam Guards had an unquenchable attraction to short women. During his tenure as guard, he had numerous clandestine affairs. In each case, children resulted. Subsequently, some of the childrenwho had no way of knowing that they were relatedmarried and had children of their own. Assume that two pairs of genes determine height. The genotype of the 7-foot-tall Potsdam Guard was A9A9B9B9, and the genotype of all of his 5-foot clandestine lovers was AABB. An A9 or B9 allele in the offspring each adds 6 inches to the base height of 5 feet conferred by the AABB genotype. a. What were the genotypes and phenotypes of all the F1 children? b. Diagram the cross between the F1 offspring, and give all possible genotypes and phenotypes of the F2 progenyIn 1995, doctors reported a Chinese family in whichretinitis pigmentosa (progressive degeneration of theretina leading to blindness) affected only males. Allsix sons of affected males were affected, but all of thefive daughters of affected males (and all of thechildren of these daughters) were unaffected.a. What is the likelihood that this form of retinitispigmentosa is due to an autosomal mutationshowing complete dominance?b. What other possibilities could explain the inheritance of retinitis pigmentosa in this family? Whichof these possibilities do you think is most likely?
- Take the example of B-thalassemia, an autosomal recessive genetic disease that particularly affects people from around the Mediterranean. This disease is associated with an anomaly of hemoglobin, a protein essential for the transport of oxygen, which is composed of four chains: two alpha (a) and two beta (B). In case of B-thalassemia, the ẞ chains are produced in insufficient or no quantity in an individual homozygous recessive resulting in insufficient production of overall hemoglobin leading to anemia and other physiological challenges. The gene that controls the synthesis of the ẞ chains is located on chromosome 11. Here is part of the coding portion of this gene (which controls a total of 146 amino acids and of which you only see the portion 36 to 41) and one of the targeted mutations: 1. Give the sequence of amino acids from the template and mutated strands. 2. What type of point mutation is it? 3. Using the principles of the theory of evolution, explain briefly and generally why…One particularly useful feature of the Hardy-Weinberg equation is that it allows us to estimate the frequency of heterozygotes for recessive genetic diseases, assuming that Hardy-Weinberg equilibrium exists. As an example, let’s consider cystic fibrosis, which is a human genetic disease involving a gene that encodes a chloride transporter. Persons with this disorder have an irregularity in salt and water balance. One of the symptoms is thick mucus in the lungs that can contribute to repeated lung infections. In populations of Northern European descent, the frequency of affected individuals is approximately 1 in 2500. Because this is a recessive disorder, affected individuals are homozygotes. Assuming that the population is in Hardy-Weinberg equilibrium, what is the frequency of individuals who are heterozygous carriers?Glucose-6-phosphate dehydrogenase (G6PD)-deficiency is another human red blood cell disease that affects 400,000 individuals worldwide every year as a result of a defective allele of the G6PD enzyme. This disorder results in crippling and sometimes fatal anemia in individuals when induced by stress, certain medications, foods (e.g. fava beans), or infection. (G6PD)-deficiency is a single-gene recessive X-linked trait. If an unaffected couple gives birth to a son with G6PD-deficiency disorder, what is the likelihood that their next child, who will be a daughter, will suffer from (G6PD)-deficiency disorder? 0% 25% 50% 75% 100%
- The following genetic map describes three hypothetical human autosomal genes, each of which exhibits two alleles. Two-factor map distances are shown. A = Artistic (dominant) a = Inartistic (recessive) M = Moral (dominant) m = Immoral (recessive) G = Generous (dominant) g = Greedy (recessive) Assume that these traits exhibit simple Mendelian dominance/recessiveness. The coefficient of coincidence for this map is 0.4. An artistic, moral, generous heterozygous female of genotype AMG/amg marries an inartistic, immoral, greedy homozygous male of genotype amg/amg. What is the probability that their firstborn child will be inartistic, immoral and greedy? What is the probability that their firstborn child will be inartistic, moral and generous? What is the probability that their firstborn child will be artistic, immoral and generous?There is an autosomal gene in cats that controls whether or not they also have white patches of fur (W = white spots, w= no white spots). Considering this along with the Orange gene (O0 and OB) from the previous question, and how it works, how many possible genotypes (using these 4 alleles) are there for cats that are orange, black, and white (in other words, calico)?Sickle cell anemia is a blood disorder that is expressed with incomplete dominance. The homozygous recessive phenotype has sickle shaped red blood cells that cause anemia and often death if untreated. If an unaffected father and mother move to the United States from Sub-Saharan Africa and several of their offspring have sickle cell anemia, what do we know about both parents' genotypes? One is homozygous recessive, the other is heterozygous They are both heterozygous They are both homozygous recessive One is homozygous dominant, the other is heterozygous
- In humans, four different blood types (A, B, AB, and O) are encoded by three alleles 1, 1, and i Individuals with both I and I alleles have blood type AB (red blood cells with both A and B antigens). Two copies of the i allele are required for an individual to have blood type O (red blood cells with no antigens). Which of the following correctly indicates the relationship between the I and / alleles for the blood type gene? Select one: OA. I is dominant to / OB. I is recessive to i OC. I and I are co-dominant OD. I and/exemplify incomplete dominanceA mutant allele in persons with familial hypercholesterolemia (FH) causes death due to a lack of liver receptors for LDL. Susceptible persons have half the normal number of receptors, while other individuals have the normal number of receptors. In a phenotypically normal couple, the man had a female 1 cousin (on his father’s side) who died from FH; the woman had a maternal uncle with FH. Using standard symbols, draw apedigree of these couple’s families. Write the genotypes of each family member.The amount of enzyme activity in a cell that is homozygous for a mutant allele is 20 units. The amount of enzyme activity in a cell homozygous for the WT allele is 10 units. It is known that 14 units of enzyme activity is required to show the trait. What is the dominance relationship between the WT and mutant allele for the phenotype of amount of enzyme per cell? A) The WT allele is dominant. B) The mutant allele is dominant. C) The WT and mutant alleles are codominant. D) The WT and mutant alleles show incomplete dominance. E) It is impossible to determine from the information given.