In humans, a very rare dominant allele that causes the little fingerto be crooked has a penetrance of 80%. In other words, 80% of heterozygotes carrying the allele will have a crooked little finger. If ahomozygous unaffected person has children with a heterozygotecarrying this mutant allele, what is the probability that an offspring will have a little finger that is crooked?

In humans, a very rare dominant allele that causes the little fingerto be crooked has a penetrance of 80%. In other words, 80% of heterozygotes carrying the allele will have a crooked little finger. If ahomozygous unaffected person has children with a heterozygotecarrying this mutant allele, what is the probability that an offspring will have a little finger that is crooked?

Name: In humans, a very rare dominant allele that causes the little fingerto
Uploaded: 2024-03-20T06:43:04.000Z
Channel: Bartleby
Description: In humans, a very rare dominant allele that causes the little fingerto be crooked has a penetrance of 80%. In other words, 80% of heterozygotes carrying the allele will have a crooked little finger. If ahomozygous unaffected person has children with

Human Biology (MindTap Course List)

11th Edition

ISBN:9781305112100

Author:Cecie Starr, Beverly McMillan

Publisher:Cecie Starr, Beverly McMillan

Chapter20: Chromosomes And Human Genetics

Section: Chapter Questions

Problem 7CT: The following pedigree shows the pattern of inheritance of red-green color blindness in a family....

See similar textbooks

Similar questions

What is a reciprocal cross? Suppose that a gene is found as a wildtype (functional) allele and a recessive mutant (nonfunctional)allele. What would be the expected outcomes of reciprocal crossesif a true-breeding normal individual was crossed to a true-breedingindividual carrying the mutant allele? What would be the results ifthe gene is maternally inherited?
In rats, hair color is either gray (G), black (g), or white. The white color is produced due to an epistatic recessive allele of gene "a". In other words, in order for the black or gray color to show up, the rat must have at least one dominant (A) epistatic allele. Two heterozygous Gray rats are crossed. Both rats are also heterozygous for the epistatic gene. Predict the probability that an offspring of this cross will: a. Express the gray phenotype b. Express the black phenotype c. Express the white phenotype
In rats, hair color is either gray (G), black (g), or white. The white color is produced due to an epistatic recessive allele of gene "a". In other words, in order for the black or gray color to show up, the rat must have at least one dominant (A) epistatic allele. Two heterozygous Gray rats are crossed. Both rats are also heterozygous for the epistatic gene. Predict the probability that an offspring of this cross will: phenotype *Be sure to express each answer as a percentage! 12pt v a. Express the gray phenotype b. Express the black phenotype c. Express the white O English Paragraph BI U Α
A mutant sex-linked trait called “notched” (N) is deadly in Drosophila when homozygous in females. Males who have a single N allele will also die. The heterozygous condition (Nn) causes small notches on the wing. The normal condition in both male and females is represented by the allele n. a) Indicate the phenotypes of the F1 generation from the following cross: XNXn x XnY b) Explain why dead females are never found in the F1 generation no matter which parents are crossed. c) Explain why the mating of female XNXn and a male XNy is unlikely.
Mendelian ratios are modified in crosses involving autotetraploids.Assume that one plant expresses the dominant trait greenseeds and is homozygous (WWWW). This plant is crossed to onewith white seeds that is also homozygous (wwww). If only onedominant allele is sufficient to produce green seeds, predict theF1 and F2 results of such a cross. Assume that synapsis betweenchromosome pairs is random during meiosis.
In dogs, black coat color (B) is dominant to yellow coat color (b), and straight fur (C) is dominant to curly fur (c). The coat color gene and the fur texture gene are on different chromosomes, so they assort independently, and are not sex-linked. In a cross between two BbCc parents, given that an offspring has black coat color and straight fur, what's the probability that it is heterozygous for both genes? Give 2 digits past the decimals.
In guinea pigs, black fur is dominant over brown fur, and short hair is dominant over long hair. These traits follow Mendelian inheritance. Suppose a homozygous short black hair is mated with a homozygous long brown haired rabbit, determine the phenotypic ratio of the following: F1 generation; F2 generation; F1 mated with a short brown haired rabbit. Gene Notation: B - hair color , S - hair length
A homozygous plant with 20-cm-diameter flowers is crossed with a homozygous plant of the same species that has 40-cm-diameter flowers. The F1 plants all have flowers 30 cm in diameter. In the F2 generation of 512 plants, 2 plants have flowers 20 cm in diameter, 2 plants have flowers 40 cm in diameter, and the remaining 508 plants have flowers of a range of sizes in between. (a) Assuming all alleles involved act additively, how many genes control flower size in this plant? (b) What frequency distribution of flower diameter would you expect to see in the progeny of a backcross between an F1 plant and the large-flowered parent?
Sickle cell anemia is a blood disorder that is expressed with incomplete dominance. The homozygous recessive phenotype has sickle shaped red blood cells that cause anemia and often death if untreated. If an unaffected father and mother move to the United States from Sub-Saharan Africa and several of their offspring have sickle cell anemia, what do we know about both parents' genotypes? One is homozygous recessive, the other is heterozygous They are both heterozygous They are both homozygous recessive One is homozygous dominant, the other is heterozygous
The pedigree shown below shows the inheritance of cystic fibrosis, a disorder that causes severe damage to the lungs and digestive system. Individual 5 shows no family history of cystic fibrosis and is considered to be homozygous for the normal allele. What is the probability that individual 10 is a carrier for the allele leading to cystic fibrosis?
In jellyfish, let's say that long tentacles are produced by a sex-influenced allele that is dominant in males and recessive in females. Let B1 = long and B2 = short. Which of the following correctly diagrams a cross between a female with long tentacles and a male with short tentacles? O B1B1XX X B1B2XY O B1B2 XX X B1B2 XY O females with long tentacles do not exist, so this cross is impossible O B1B1 XX X B2B2 XY O X(B1) X(B2) x X(B2) Y
#1 a) An allele for coat color in mice, Y, produces a yellow coat color when present. The phenotypes of the F1 generation are shown. A cross between a Non-yellow mouse and yellow mouse produces half yellow and half non-yellow progeny (offsprings). Non-yellow happens to be white in this example, but it does not need to be; it can be black, grey, or some other mouse color. Identify the genotype of the "Dead" phenotype. Describe the rationale behind your genotypic selection. * Pgeneration Yellow Non-yellow Yellow Yellow Gametes Y Meiosis Fertilization 1/2 1/2 Yellow Non-yellow Fi generation Yellow Yellow Non-yellow Dead Support | Schoology Blog | PRIVACY POLICY | Terms of Use INTL