In a simple electric circuit, Ohm's law states that V = IR, where V is the voltage in volts, I is the current in amperes, and R is the resistance in ohms. Assume that, as the battery wears out, the voltage decreases at 0.04 volts per second and, as the resistor heats up, the resistance is increasing at 0.02 ohms per second. When the resistance is 300 ohms and the

Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter23: Resistive-inductive-capacitive Series Circuits
Section: Chapter Questions
Problem 1RQ: What is the phase angle relationship of current and the voltage dropped across a pure resistance?
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In a simple electric circuit, Ohm's law states that
V = IR, where V is the voltage in volts, I is the
current in amperes, and R is the resistance in ohms.
Assume that, as the battery wears out, the voltage
decreases at 0.04 volts per second and, as the resistor
heats up, the resistance is increasing at 0.02 ohms per
second. When the resistance is 300 ohms and the
current is 0.01 amperes, at what rate is the current
changing?
amperes per second
Transcribed Image Text:In a simple electric circuit, Ohm's law states that V = IR, where V is the voltage in volts, I is the current in amperes, and R is the resistance in ohms. Assume that, as the battery wears out, the voltage decreases at 0.04 volts per second and, as the resistor heats up, the resistance is increasing at 0.02 ohms per second. When the resistance is 300 ohms and the current is 0.01 amperes, at what rate is the current changing? amperes per second
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