In a hypothetical situation, brachydactyly is caused by a recessive allele (b). If a woman who is heterozygote with normal fingers (Nb) and a man with brachydactyly (bb) have children, what proportion of these children would you expect to have normal fingers? (You may want to draw the punnett square on a scrap piece of paper). Group of answer choices A-50% B-0% C-75% D-100% E-25%
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- A sex-linked recessive allele rg causes a red-green colorblindness in humans. A normal woman whose father was colorblind marries a colorblind man. A. What genotypes are possible for the mother of the colorblind man? B. What are the chances that the first child from this marriage will be a colorblind boy? C. Of the girls born from this union, what proportion can be expected to be colorblind? D. Of all the children of these parentsIn 1927, the ophthalmologist George Waaler tested9049 schoolboys in Oslo, Norway, for red-green colorblindness and found 8324 of them to be normal and725 to be color blind. He also tested 9072 schoolgirlsand found 9032 that had normal color vision while40 were color blind.a. Assuming that the same sex-linked recessive allelec causes all forms of red-green color blindness,calculate the allele frequencies of c and C (the allelefor normal vision) from the data for the schoolboys.(Hint: Refer to your answer to Problem 12a.)b. Does Waaler’s sample demonstrate Hardy-Weinbergequilibrium for alleles of this gene? Explain youranswer by describing observations that are eitherconsistent or inconsistent with this hypothesis.On closer analysis of these schoolchildren, Waalerfound that there was actually more than one c allelecausing color blindness in his sample: one kind forthe prot type (cp) and one for the deuter type (cd).(Protanopia and deuteranopia are slightly differentforms of red-green…Black eye (B) is dominant over brown eye (b). A man that is a homozygous dominant black-eyed marries a woman that is a heterozygous black-eyed. The offspring resulted to 50% homozygous black and 50% heterozygous black. If one of their heterozygous children marries another heterozygous partner. Regardless of its gender, what are the genotypes of their children? a. 25% BB, 50% Bb, 25% bb b. 50% BB, 25% Bb, 25% bb c. 25% BB, 25% Bb, 50% bb d. 0% BB, 75% Bb, 25% bb In Law of Codominance, a pure line dominant trait crossed with a recessive trait will result to the appearance of both dominant and recessive trait in the offspring. What is the percentage of having a red-haired offspring if the parental genotype is both a heterozygous roan haired? Red hair is a dominant trait and white hair is a recessive trait. a. 100% b. 75% c. 50% d. 25% e. 0%
- Phenotypic ratio: red : pink : white Solve the following genetic problems involving incomplete dominance. You must pick the right letter to represent the gene in the question. You must show your work using the Punnett square. 15. A rooster with grey feathers is mated with a hen of the same phenotype. Among their offspring 15 chicks are grey, 6 are black and 8 are white. a. What is the simplest explanation for the inheritance of these colors in chickens? b. What offspring would you expect from the mating of a grey rooster and a black hen?The chart below is showing 4 generations of a family that is affected by a hereditary disease. a. Is the disorder being tracked dominant or recessive? How do you know? b. There is only one possible genotype for person C. True or False? c. What are the possible genotypes for person A? d. What are the possible genotypes for person B?, e. If two people with the same genotypes as person C's spouse and person A's spouse had a child, what is the probability that the child will be affected by this genetic disorder? (draw a Punnett square using the correct genotypes to help you). % chance offspring will be affected % chance offspring will not be affectedin earlobes, attached (A) earlobe is dominant while free (f) earlobe is recessive. - free earlobes with heterozygous dominant for attached earlobes? (percent) - heterozygous for attached earlobes with heterozygous for attached earlobes. (percentage) - Homozygous dominant for attached earlobes with free earlobes. (Answer in percent)
- An allelic series determines coat color in rabbits: C (full color), c (chinchilla, gray color), c` (Himalayan, white with black extremities), and c (albino, all white). The C allele is dominant over all others, c is dominant over over c, and c is recessive to all other alleles. This dominance hierarchy can be summarized as C > c the table are crossed and produce the progeny shown. h Cc X c c Parents full color × albino Himalayan x albino full color x albino full color × Himalayan full color X full color Cross A B C D 50% full color, 25% Himalayan, 25% albino 75% full color, 25% albino E Match the parental genotypes to the letter corresponding to the appropriate cross listed in the table. A CC x cc VIV B Cc x Cc Offspring 50% full color, 50% albino 50% Himalayan, 50% albino 50% full color, 50% chinchilla Cc x cc C Answer Bank h с с X сс ch Cc xcc D h h с с X сс and c, c is dominant > c> c. The rabbits in EIn humans, curly hair is dominant to straight hair. A woman heterozygous for curly hair marries a man with straight hair and they have children. a. What is the probability that the first child will have curly hair? b. What is the probability that in a family of four children 3 will be curly and 1 will be straight haired? c. What is the probability that the first three children will be curly-haired girls and the next will be a straight haired boy?In the example below, crossing you left thumb over your right thumb is dominant T to crossing your right over left recessive t. Identify the genotype of the individual shown below: OShutterstock / robynleig O A. homozygous dominant (TT) O B. heterozygous dominant (Tt) or homozygous dominant (TT) OC. homozygous recessive (tt) O D. Cannot be determined from information provided
- Bronze coloured turkey is controlled by a dominant allele, B. Red coloured turkey is homozygous for a recessive allele bb. Dominant gene N produce normal feather and recessive genotype produce ‘hairy’ feather nn. In a cross between homozygous bronzed coloured turkey with ‘hairy’ feather and homozygous red coloured turkey with normal feather. What are the ratios of F2 progeny with Bbnn genotypes? (I want to check if what i'm doing is correct)15. The following pedigree shows inheritance of Huntington's disease, a fatal genetic disorder that causes neurodegeneration. Since signs and symptoms usually do not appear until adulthood, many who are carriers may not realize their risk of passing on the disease-causing allele. The following pedigree represents a family in which some people are affected by Huntington's disease. Reeessive Trit er btmnt be Mec yplicalty HinheteeQuestions a to e are answerable by yes or no. Indicate the possible parental genotypes if your answer is yes.a. Can a man with hairy ears have a hairy-eared daughter?b. Can two normal parents produce a colorblind son?c. Can two normal parents produce a colorblind daughter?d. Can a colorblind woman have a normal son?e. Can a bald man have a nonbald daughter?