Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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- In chickens the dominant gene (S) produces pea-shaped crest and its recessive allele (s) simple crest.The Andalusian condition (AA *) is an intermediate expression of the genes for black (A) and white (A *) From the following cross between two Andalusian birds-Heterozygous Pea Determine the PHENOTYPIC RATIO OF THEIR DESCENDANTS. 1. 3/4 Pea Black and 1/4 Simple White 2. 3/16 Black Pea, 1/16 Simple Black, 3/16 Andalusian Pea, 1/16 Simple Andalusian, 3/16 White Pea and 1/16 Simple White 3. 9/16 Simple Black, 3/16 Andalusian Pea, 3/16 Simple White and 1/16 Simple White 4. 3/16 Black Pea, 1/16 Simple Black, 6/16 Andalusian Pea, 2/16 Andalusian Simple, 3/16 White Pea and 1/16 White Simplearrow_forwardMendel's Laws of Inheritance Menders Success Menders approach to the study of heredity was effective for several reasons. Foremost was his choice of experimental subject, the pea plant Pisum sativum. Monohybrid Crosses Mendel began by studying monohybrid crosses— those between parents that differed in a single characteristic. The principle of segregation (Mendel's first law) states that each individual diploid organism possesses two alleles for any particular characteristic. These two alleles segregate (separate) when gametes are formed, and one allele goes into each gamete. Furthermore, the two alleles segregate into gametes in equal proportions.The concept of dominance that, when two different alleles are present in a genotype, only the trait of the dominant allele is observed in the phenotype. Multiple-Loci Crosses Dihybrid Crosses In addition to his work on monohybrid crosses, Mendel also crossed varieties of peas that differed in two characteristics (dihybrid crosses).…arrow_forward+Why is it important to study genetics?arrow_forward
- 3) In the snail Capaea nemoralis, an autosomal allele causing a banded shell (B®) is recessive to the allele for an unbanded shell (B°). Genes at a different locus determine the background color of the shell; here yellow (C') is recessive to brown (CBw). A banded, yellow snail is crossed with a homozygous brown, unbanded snail. The F1 are then crossed with banded, yellow snails (a test cross). a. What will the results of the testcross be in the loci that control banding and color ARE linked with NO crossing over.arrow_forwardplease help don't need a detailed explanationarrow_forwardNeed help with problemarrow_forward
- 7- In peas, a tall, yellow- seeded plant is crossed with a homozygous short, green- seeded plant and yields 203 tall, green-seeded plant, 199 short, green seeded plants, 207 tall, yellow-seeded plants, and 192 short, yellow-Seeded plants. The most likely genotype of the tall, yellow-seeded plant is.. [EXPLAIN by drawing the punnett square that reflects this phenomena then select the right answer/4 a) TtYy b) TTYY c) Ttyy d) ttYYarrow_forwardIn silk moths red eyes (r) and white banded wing (w) are recessive to normal eyes (R) and 10m.u. apar normal wings (W). A moth homozygous for red eyes and white banded wings is crossed with an individual who is homozygous normal for both traits. The F, progeny are testcrossed with the following progeny produced: Normal eyes, normal wings Red eyes, normal wings 19 Normal eyes, white banded wings Red eyes, white banded wings 426 a. What phenotypic proportions would be expected if the genes for red eyes and white banded wings were located on different chromosomes? b. What is the genetic distance between these two genes? 418 16arrow_forwardCoat color in an elusive (and not necessarily real) mutated mongoose in Puerto Rico is governed by multiple alleles. The order of decreasing dominance for these alleles is as follows: black (B), buff, (B", brown (B') and albino (b). What phenotypic ratios are observed from a BB' X B'b cross? all brown O 2 black: 2 Brown O 1 black: 1 buff 2 black: 1 buff: 1 brown 2 brown :1 buff : 1 albino O 2 buff: 1 black: 1 albinoarrow_forward
- It would be nice if you can give me some explanation please Number 6arrow_forwardPrinciples of Heredity 667 Activity 1 Working Out Crosses Involving Dominant and Recessive Genes For each of the following crosses, draw your own Punnett square and use the technique outlined above to determine the genotypes and phenotypes of the pea plant offspring 2. Genotypes of parents: Tt (3) × Tt (Q) % of each genotype: 1. Genotypes of parents: Tt (3) × tt (9) % of each phenotype: % tall, % dwarf % of each genotype: 3. Genotypes of parents: TT (3) X Tt (2) % of each phenotype: % tall, % dwarf % of each genotype: % of each phenotype: % tall, % dwarf Incomplete Dominance uhot alleles exnress themselves in the offspring. The crosses arearrow_forward
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