If I have an input sine wave in a peak detector circuit I know the output the the first op amp (that will feed back into the negative terminal) should be a little larger than the input (this is why you add a second op amp). I'm not understanding it graphically. Splitting up the circuit say you have the first op amp and the diode (no capacitor or second op amp). the output should be only the positive part of sine wave, and the amplitude will be the amplitude input minus .6V from the diode drop, right? Then adding the capacitor it keeps the same amplitude but makes more DC. with the second op amp this makes it so the capacitor doesn't discharge (which is what keeps the voltage proper up I think?) With my logic here, the voltage feeding back into the first op amp negative terminal is the voltage input, minus a diode drop. So Vin > V- (voltage feeding back into the negative terminal). Which I'm pretty sure V- is supposed to be larger. So I think I'm misunderstand something here. Please correct any of my explanation or add anything I'm that would explain voltage in vs voltage out of a peak detector if you were feeding in like a constant sin wave.
Power Amplifier
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If I have an input sine wave in a peak detector circuit I know the output the the first op amp (that will feed back into the negative terminal) should be a little larger than the input (this is why you add a second op amp). I'm not understanding it graphically.
Splitting up the circuit say you have the first op amp and the diode (no capacitor or second op amp). the output should be only the positive part of sine wave, and the amplitude will be the amplitude input minus .6V from the diode drop, right?
Then adding the capacitor it keeps the same amplitude but makes more DC. with the second op amp this makes it so the capacitor doesn't discharge (which is what keeps the voltage proper up I think?)
With my logic here, the voltage feeding back into the first op amp negative terminal is the voltage input, minus a diode drop. So Vin > V- (voltage feeding back into the negative terminal). Which I'm pretty sure V- is supposed to be larger. So I think I'm misunderstand something here. Please correct any of my explanation or add anything I'm that would explain voltage in vs voltage out of a peak detector if you were feeding in like a constant sin wave.
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