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I need help with a chemistry question
Which one of the following compounds contains an ion with a 3+ charge?
- KCl
- Na2O
- CuCl
- FeCl3
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- 1) BCE: Type: 2) BCE: Type: 3) BCE: Type: 4) BCE: Type: 5) BCE: Type: Fe C3H6O Pb(NO3)2 H₂CO3 ◆ H₂O₂ ◆ ◆ + ◆ ◆ + ◆ + ◆ + Cl₂ 0₂ NaCl NaOH H₂O O ◆ ( O « + FeCl3 CO₂ PbCl₂ 0₂ O ◆ Na₂CO3 → + ◆ + ◆ + H₂O NaNO3 H₂O « ♦ ◆U-235 and U-238 are the two ________________ of Uranium which vary in the number of neutrons in their nucleus. isomers isotones isobars isotopesI need help with a chemistry question: The compound MgCl2 is named __________. Group of answer choices magnesium chlorine magnesium dichloride magnesium (II) chloride magnesium chloride dimagnesium chloride
- Why not 3?Which name of this compound [Al F6]??keAssignment/takeCovalentActivity.do?locator-assignment-take MI 2req 2req (X) 2req 2req 2req 2req 2req 2req A compound is found to contain 7.962 % silicon, 20.10 % chlorine, and 71.94 % iodine by mass. What is the empirical formula for this compound? To answer the question, enter the elements in the order presented above. Submit Answer Use the References to access important values if needed for this question. K Retry Entire Group 9 more group attempts remaining Previous Next 14 * - 0
- kamalaa.n:1 love Tt ll 5G 1 TikTok 2H+ (ag) + 2e-- H2 (g) 0.000 2H20 (1) + 2e" - H2 (9) + 20H" (aq) -0.8277 H202 (aq) + 2H+ (aq) + 2e + 2H20 (1) 1.776 I2 (s) + 2e - 21 (aq) 2103- (aq) + 12H+ (aq) + 10e- + 12 (s) + 6H20 (1) 0.5355 1.195 Mg2+ (aq) + 2e + Mg (s) -2.372 Mn2+ (ag) + 2e" Mn (s) -1.185 Mno, + 4H+ (aq) + 2e - Mn2+ (aq) + 2H20 (1) 1.224 Mno4 (aq) + 8H+ (aq) + 5e" - Mn2+ (aq) + 4H20 (1) 1.507 Mno4 (aq) + 2H20 (1) + 3e - MnO2 (s) + 40H (aq) 0.595 HNO2 (aq) + H* (aq) + e- NO (g) + H20 (1) 0.983 N2 (9) + 4H20 (1) + 4e" - 40H" (aq) + N2H4 (aq) -1.16 NO3 (aq) + 4H* (aq) + 3e" - NO (9) + 2H20 (1) 0.957 Na* (aq) + e - Na (s) -2.71 Ni2+ (aq) + 2e- Ni (s) -0.257 02 (9) + 4H* (aq) + 4e" - 2H20 (1) 1.229 0.401 O2 (9) + 2H2O (1) + 4e - 40H (aq) 0.695 O2 (9) + 2H* (aq) + 2e - H2O2 (aq) -0.1262 Pb2+ (aq) + 2e"- Pb (s) -0.3588 PbSO4 (s) + H* (aq) + 2e Pb (s) + HSOA (ag) k Air 4) FII F10 F9 F7 F8 deleteCa3(PO4)2 + H2SO4 CaSO4 Ca(H,PO)2 - - 10. H3PO4 HCI PCI5 H;O - - | http://chemistry.about.com Chemistry 9.O Course Home b Chemistry Question | bartleby G indivuials with austium good to -> A openvellum.ecollege.com/course.html?courseld=16561285&OpenVellumHMAC=446c877376a9bc7ac878d8ad119f4717#10001 Q * E Apps G Gmail O Maps E Connect - To Do As... с ОССС Мoodle P chem work b help Balance Chemical E. YouTube Part A Classify the following molecule according to its functional group. H H H | H-C-C-N-C-C-H | | | | H H H H Enter the name of the class of organic compound. • View Available Hint(s) This molecule is classified as a(n) Submit Part B Classify the following molecule according to its functional group. CH3CH2CH2COOH The molecule contains a(n) functional group. Submit Request Answer 11:01 PM O Type here to search 99+ 3/2/2021 I-Z
- mHMAC3ccdb6aa11676716c83835709749d96e5#10001 Translate Reading list 1 of 11 I Review | Constants Periodic Table Part A Julia spent $50 on a book. The cost of the book was $18 less than twice what she spent on a backpack. How much did the backpack cost? Express your answer numerically in dollars. • View Available Hint(s) Hint 1. Identify the mathematical equation Hint 2. Identify the expression for the cost of the backpackO Course Home b Chemistry Question | bartleby G indivuials with austium good to -> A openvellum.ecollege.com/course.html?courseld=16561285&OpenVellumHMAC=446c877376a9bc7ac878d8ad119f4717#10001 Q * E Apps G Gmail O YouTube O Maps E Connect - To Do As... ОССС Мoodle P chem work b help Balance Chemical E. Course HOmEstudent found a bottle of unknown origin in the basement of an "CAUTION—contains С₁H₁O.” No other A old house. The bottle was labelled information was given, but inside the bottle were some white crystals. The student took the bottle to a chemistry laboratory, where she analyzed the crystals with the help of the laboratory staff. C₁2H₁6O reacted with Br₂ in CCl4 adding one mole of Br, and forming C₁₂H₁OB2₂. When a sample of C₁₂H₂O was reacted with O3 followed by Zn/H₂O, two different samples, J and K, were obtained. Compound J had a molecular formula of C.HgO₂, and its NMR is shown below. Compound K had a molecular formula of C₂H₂O, and it could be oxidized to compound L, with a molecular formula of C₂H₂O₂. The IR spectrum of L showed a very wide, strong band centred around 3000 cm*¹. The NMR spectrum of L showed only two different absorptions: a doublet (6H) at 0.9 ppm and a septet (1H) at 3.6 ppm. There was also a singlet (1H) off the scale at 11.8 ppm. students, deduce possible…SEE MORE QUESTIONS