I have the following code for finding the next permutation: #include #include using namespace std; int main() { int max = 3; int arr[max] = { 1, 2, 3}; do { cout << arr[0] << " " << arr[1] << " " << arr[2] << " " << arr[0] << "\n"; } while (next_permutation(arr + 1, arr + max)); cout << "After loop: " << arr[0] << ' ' << arr[1] << ' ' << arr[2] << '\n'; return 0; } It gives me the following output: 1 2 3 1 1 3 2 1 After loop: 1 2 3 Now, I am wondering why the permutation would stop at 1321 and why would it order it in such a way.
I have the following code for finding the next permutation: #include #include using namespace std; int main() { int max = 3; int arr[max] = { 1, 2, 3}; do { cout << arr[0] << " " << arr[1] << " " << arr[2] << " " << arr[0] << "\n"; } while (next_permutation(arr + 1, arr + max)); cout << "After loop: " << arr[0] << ' ' << arr[1] << ' ' << arr[2] << '\n'; return 0; } It gives me the following output: 1 2 3 1 1 3 2 1 After loop: 1 2 3 Now, I am wondering why the permutation would stop at 1321 and why would it order it in such a way.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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I have the following code for finding the next permutation:
#include <iostream>
#include <algorithm>
using namespace std;
int main()
{
int max = 3;
int arr[max] = { 1, 2, 3};
do {
cout << arr[0] << " " << arr[1] << " " << arr[2] << " " << arr[0] << "\n";
} while (next_permutation(arr + 1, arr + max));
cout << "After loop: " << arr[0] << ' '
<< arr[1] << ' ' << arr[2] << '\n';
return 0;
}
It gives me the following output:
1 2 3 1
1 3 2 1
After loop: 1 2 3
Now, I am wondering why the permutation would stop at 1321 and why would it order it in such a way.
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