How could you distinguish between the following isomers by 13C-NMR: a. 1,2-Dimethylbenzene b. 1,3-Dimethylbenzene C. 1,4-Dimethylbenzene.

Which of the following molecules: A. H₂C 0 CH₂ C. Ï_¶Ï H₂C B. H₂C A. acetone C. ethanol OH B. methyl acetate E. ethyl acetate D. diethyl ether is best represented by NMR spectra below? D. 20 H.C 17122 .CH₂₁ 14 E. H₂C 10 20 13C

Biochemistry HW question 21 need help

The 1H NMR spectrum in the figure corresponds to which of the substances indicated? (1). Chlorobenzene (2). 1,1,2-trichloroethane (3). Chloroethane (4). Ethane 8 Triplete Integral: 2.03 7 Doblete Integral: 3,99 6 5 4 3 2 1 08, ppm

Using the tables, answer the 2 questions at the bottom.

Consider the following three compounds: cyclohexanol, 2-butanone, and 2-butanol. Using HETCOR (IH vs. 13C two dimensional NMR), which of the compounds above could show at least one carbon atom bearing two hydrogens with different chemical shifts. • A. cyclohexanol only O B. cyclohexanol and 2-butanone O C. cyclohexanol and 2-butanol O D. 2-butanone only

WYY 9. 8 7 6. 4 PPM 3 1 0. Which of the following structures matches the 'H-NMR spectum provided above? H A) HH C' H. H B) H-C H D) HH C C) H-C C, C' H. H. C' C H-CCNO2 TH. Hc^NO2 H. 8.219 8.169 8.151 1.002 900 [ 1.003 | 1.001 0.987 5.270 | 1.998 4.608 2.

1. (Chapter 13 - Q57) The H and 1C NMR spectra of compound A, CaH9Br are sho below. Answer the following questions. Chem. Rel. shift area 1.20 3.00 2.58 2.00 2.00 2.00 707 7.39 TMS 10 O ppm 4 Chemical shift (8) TMS 200 180 160 140 120 100 Chemical shift (8) O ppm 20 1(a) Degree of the unsaturation of this compound is - 1(b) The derived unsaturation number indicates that compound has . a(c) Two peaks in between 6.5 - 8.0 0 indicate that compound is 1(d) According to the splitting pattern of the peak at 1.20 d and 2.58 ð indicates that compound has a. - group= 1(e) According to the H NMR spectrum the number of nonequivalent aromatic prot sets in the compound - 1(1) According to the 19C NMR, the number of nonequivalent carbons in the compou 1(g) According to your answer in Q 1(f) the compound has a plane of symmetry Yes a NO = 1(h) The IUAC name for this unknown compound is = Intensity- Intensity

Based on the NMR, why is Ethylbenzene the structure of the compound and not 1,2-Xylene, 1,3-Xylene, or 1,4-Xylene?

Homotopic, Enantiotopic, Diastereotopic