Hemophilia is caused by an X-linked recessive mutation in humans. If a woman whose paternal uncle (father's brother) was a hemophiliac marries a man whose brother is also a hemophiliac, what is the probability of their first child having hemophilia (Note: assume that there are no other cases of hemophilia in the pedigree and no hidden carriers)? Select one: a. 1/2 b. 1/8 c. 0 d. 1/4 e. 1 O

Cystic fibrosis in humans is caused by mutations in a single gene and is inherited as an autosomal (non-sex chromosome) recessive trait. An unaffected couple has two children. The first child has cystic fibrosis, and the second child is unaffected. What is the probability that the second child is a carrier (heterozygous) for the mutation that causes the disease? 2/3 1 1/2 3/4

Gregor Mendel discovered the basis of heredity with his sweet pea plant experiments. In his studies, he determined that certain traits, such as pod color and pea shape, express complete dominance. A cross occurs between a plant with heterozygous yellow pods and wrinkled peas and a plant with green pods and heterozygous round peas. What is the probability that the offspring will exhibit recessive genes for both traits? A - 1/2B - 1/4C - 1/8D - 1/16

Albinism in humans is autosomal and fully recessive to normal color. A couple, who are both normal, have a daughter who is albino and a son who is normal. What is the probability that their normal son is a carrier of the albinism gene?

a) Which of the four modes of inheritance are consistent with the disease shown in this human pedigrees below? (List the compatible mode or modes) Give an answer for a, b and c b) If the parents in pedigree c have 2 other children, what is the probability that they will carry the disease?

In a dihybrid cross (2 sets of alleles, independently assorted) each parent (heterozygous for both traits) can have 4 combinations of alleles in their gametes), so to calculate the odds for inheritance of particular genetic combinations, we must draw out 16 squares. In the case of our purple/yellow and starchy/sweet corn kernels, we can calculate the odds of the possible phenotypes. Purple & starchy: purple & sweet: yellow & starchy: yellow & sweet, can be calculated as O 9:2:2:3 9:3;3;1 O 5:4:4:3

Joanne has AB blood and Henry has AB blood. They have one child with A blood, one child with AB blood, and another child that has O Bombay phenotype blood. Please explain what is happening here. What is the chance that Joanne and Henry will have a child with B blood type? What is the name of the phenomenon that is responsible for the Bombay phenotype?

Duchenne muscular dystrophy is an inheritable disorder that results in muscle weakness, leading to walking and breathing difficulties and heart disease. Which of the following is a valid conclusion about the Duchenne muscular dystrophy pedigree shown above? Select one: a. Only individuals I-2 and II-4 are confirmed carriers of the Duchenne muscular dystrophy allele. b. Individual II-3 can only pass on the Duchenne muscular dystrophy allele to individuals III-2 and III-4. c. Without further evidence, the genotypes of individuals II-2 and III-2 cannot be determined. d. Only individuals I-1 and II-3 are confirmed carriers of the Duchenne muscular dystrophy allele.

A mother is heterozygous for the X-linked gene for colorblindness and also heterozygous for the autosomal inherited sickle cell anemia. She is married to a man who can see color normally and who is heterozygous for sickle cell trait. Using b (colorblind), B (normal color), S (normal hemoglobin), s (sickle cell), answer the following: a. What are the genotypes of the parents? b: What is the probability of having a child who is both color blind and has sickle cell anemia?