Genes a and b are 20 cM apart. An a+ b+/a b individual was mated with an a b/a b individual. Which of the following is not true: Group of answer choices a and b are autosomal alleles for a and b are in the a cis configuration alleles for a and b are in the a trans configuration a and b are linked
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- A family is tested for spinal muscular atrophy, an autosomal recessive disease, using RFLP. The normal gene can be digested with a specific enzyme, while the mutant cannot. According to the pedigree below, which of the following is most likely the RFLP results?What is the most likely order of the linked genes R, S, and T if the distance between R and S is 22 cM, the distance between S and T is 8cM, and the distance between R and T is 14 cM? A. R S T B. T R S C. Cannot be determined D. S T RThere are two genetic disorders that result from mutation in imprinted genes: Prader-Willi syndrome, Angelman syndrome. Angelman syndrome results from deletion of UBE3A, which is a gene imprinted such that only the maternal copy is expressed. In the pedigree above, individual I-1 is heterozygous for a deletion of UBE3A and does not have Angelman syndrome. Individual I-2 is homozygous wild type for UBE3A. Which individuals in the pedigree are at risk for exhibiting Angelman syndrome, if any? (Who could potentially have the syndrome, based on what alleles it is possible for them to inherit and express?) Question 8 options: Only I-1 could have been at risk. If he does not have the syndrome, no one in the pedigree could. Only III-1 is at risk I-1, II-2, and III-1 are all at risk Only II-2 is at risk No one in the pedigree is at risk Both II-2 and III-1 are at…
- If the 12/23 rule is violated then two similar segments can become part of the same gene.Which of the following statements about paramutation is false?a. A paramutagenic allele can alter the expression of paramutableallele.b. A paramutagenic allele has a lower level of expression comparedto a paramutable allele.c. The paramutation alters the DNA sequence of the paramutagenicallele.Drosophila females heterozygous for three recessive mutations, a, b, and c , were crossed to males homozygous for all three mutations.The cross yielded the following results: in the image Q. Construct a linkage map showing the correct order of these genes and estimate the distances between them.
- Some sweet-pea plants have purple flowers and others have white flowers. A homozygous variety of sweet pea that has purple flowers is crossed with a homozygous variety that has white flowers. All the F1 have purple flowers. When these F1 self-fertilize, the F2 appear in a ratio of 916 purple to 716 white. a. Give genotypes for the purple and white flowers in these crosses. b. Draw a hypothetical biochemical pathway to explain the production of purple and white flowers in sweet peasTwo plants with white flowers, each from true-breeding strains, were crossed. All the F1 plants had red flowers. When these F1 plants were intercrossed, they produced an F2 consisting of 177 plants with red flowers and 142 with white flowers. (a) Propose an explanation for the inheritance of flower color in this plant species. (b) Propose a biochemical pathway for flower pigmentation and indicate which genes control which steps in this pathway.An ear of corn has a total of 381 grains, including 216 Purple & Smooth, 79 Purple & Shrunken, 65 Yellow & Smooth, and 21 Yellow & Shrunken. This ear of corn was produced by a dihybrid cross (PpSs x PpSs) involving two pairs of heterozygous genes resulting in a theoretical (expected) ratio of 9:3:3:1. Use a chi square
- A female animal with genotype A/a ⋅ B/b is crossed with a double-recessive male (a/a ⋅ b/b). Their progeny include 442 A/a ⋅ B/b, 458 a/a ⋅ b/b, 46 A/a ⋅ b/b, and 54 a/a ⋅ B/b. Explain these results.A rare blinding disease that has a relation to dengenerative factors is partially penetrant. In the following pedigrees for two families, the affected symptomatic individuals (black circles and squares) have been diagnosed with this disease due to the mutation in mitochondrial DNA m.14484T>C. If III.4 is homoplasmic for m.14484T>C in hair, blood, urine and other tissues examined. What will occur with IV.7 then?The gene controlling ABO blood type and the gene underlying nail-patella syndrome are said to show linkage. What does that mean in terms of their relative locations in the genome? What does it mean in terms of how the two traits are inherited with respect to each other?